Answer:
The child has 6 dimes and 5 quarters.
Step-by-step explanation:
Let q and d represent the number of quarters and of dimes respectively.
Then q + d = 11 (Equation A), and ($0.25/quarter)q + ($0.10/dime)d = $1.85 (Equation B).
Multiply the 2nd equation by 100 to remove the decimal fractions:
25q + 10d = 185 (Equation C)
Now multiply the 1st equation by -10 to obtain -10q - 10d = -110 (Equation D), and combine this result with Equation C:
-10q - 10d = -110
25q + 10d = 185
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15q = 75, and so q = 75/15 = 5.
According to Equation A, q + d = 11. Replacing q with 5, we get:
5 + d = 11, and so d = 6.
The child has 6 dimes and 5 quarters.
Answer:
In (3x)^2, you are squaring both the 3 and the x:
9x^2
in 3x^2, you are squaring just the x:
3x^2
Answer:
or 
Step-by-step explanation:
Answer:
Neither A nor B
Step-by-step explanation:
The set of pairs, where the front member of every sequence pair must be unique.
The best and the most correct answer among the choices provided by the question is the first choice. The two students that set up the problem correctly is <span> Moe: x = (5 - 1)2 + (1 - 4)2 and Jimmy: x2 = 32 + 42.</span> I hope my answer has come to your help. God bless and have a nice day ahead!
