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Anvisha [2.4K]
1 year ago
11

A six sided die is rolled and a coin is tossed. Find P(odd and T).

Mathematics
1 answer:
Tasya [4]1 year ago
4 0

The probability of getting tails and rolling an odd number is P = 0.25

<h3>How to get the probability?</h3>

The probability of getting tails on the coin is 0.5

On the dice, there are 6 numbers and 3 are odd, so the probability of rolling an odd number is:

p = 3/6 = 0.5

The joint probability (of getting tails and rolling an odd number) is equal to the product between the individual probabilities:

P(odd and T) = 0.5*0.5 = 0.25

If you want to learn more about probability:

brainly.com/question/25870256

#SPJ1

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PSYCHO15rus [73]
498 is approximately 500

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500/10 = 50



So, 498/12 is approximately 50.
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3 years ago
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Identify the solutions to the quadratic equation 6x^2+x-1=0
tigry1 [53]

Answer:

1/3 and -1/2

Step-by-step explanation:

You can use the factoring method to identify the solutions of x

6x^2+x-1

2 numbers have to multiply to 6 and subtract to 1 because x is the same as 1x

So, you get 3x and 2x

since you know that -1x1 is -1 you will get

(3x-1)(2x+1)=0

Now, since (3x-1) and (2x+1) multiply to get 0, if either (3x-1) or (2x+1) is 0 the statement will be valid

3(1/3)-1=0

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So, your answers are 1/3 and -1/2

5 0
1 year ago
Which table represents a linear function?​
Andrew [12]

Answer:

The first table is the only table representing a linear function.

Step-by-step explanation:

<em>" You can tell if a table is linear by looking at how X and Y change. If, as X increases by 1, Y increases by a constant rate, then a table is linear. You can find the constant rate by finding the first difference. This table is linear."</em>

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<em>( thanks to G00GLE for the anwers, hat's off to the internet :^) </em>

8 0
3 years ago
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The manager of a music store has kept records of
Marysya12 [62]

Answer:

(a) P(x\le 3) = 0.75

(b) P(x\le 3) = 0.75

<em>(b) is the same as (a)</em>

(c) P(x \ge 5) = 0.10

(d) P(x = 1\ or\ 2) = 0.55

(e) P(x > 2) = 0.45

Step-by-step explanation:

Given

\begin{array}{ccccccc}{CDs} & {1} & {2} & {3} & {4} & {5} & {6\ or\ more}\ \\ {Prob} & {0.30} & {0.25} & {0.20} & {0.15} & {0.05} & {0.05}\ \ \end{array}

Solving (a): Probability of 3 or fewer CDs

Here, we consider:

\begin{array}{cccc}{CDs} & {1} & {2} & {3} \ \\ {Prob} & {0.30} & {0.25} & {0.20} \ \ \end{array}

This probability is calculated as:

P(x\le 3) = P(1) + P(2) + P(3)

This gives:

P(x\le 3) = 0.30 + 0.25 + 0.20

P(x\le 3) = 0.75

Solving (b): Probability of at most 3 CDs

Here, we consider:

\begin{array}{cccc}{CDs} & {1} & {2} & {3} \ \\ {Prob} & {0.30} & {0.25} & {0.20} \ \ \end{array}

This probability is calculated as:

P(x\le 3) = P(1) + P(2) + P(3)

This gives:

P(x\le 3) = 0.30 + 0.25 + 0.20

P(x\le 3) = 0.75

<em>(b) is the same as (a)</em>

<em />

Solving (c): Probability of 5 or more CDs

Here, we consider:

\begin{array}{ccc}{CDs} & {5} & {6\ or\ more}\ \\ {Prob} & {0.05} & {0.05}\ \ \end{array}

This probability is calculated as:

P(x \ge 5) = P(5) + P(6\ or\ more)

This gives:

P(x\ge 5) = 0.05 + 0.05

P(x \ge 5) = 0.10

Solving (d): Probability of 1 or 2 CDs

Here, we consider:

\begin{array}{ccc}{CDs} & {1} & {2} \ \\ {Prob} & {0.30} & {0.25} \ \ \end{array}

This probability is calculated as:

P(x = 1\ or\ 2) = P(1) + P(2)

This gives:

P(x = 1\ or\ 2) = 0.30 + 0.25

P(x = 1\ or\ 2) = 0.55

Solving (e): Probability of more than 2 CDs

Here, we consider:

\begin{array}{ccccc}{CDs} & {3} & {4} & {5} & {6\ or\ more}\ \\ {Prob} & {0.20} & {0.15} & {0.05} & {0.05}\ \ \end{array}

This probability is calculated as:

P(x > 2) = P(3) + P(4) + P(5) + P(6\ or\ more)

This gives:

P(x > 2) = 0.20+ 0.15 + 0.05 + 0.05

P(x > 2) = 0.45

3 0
3 years ago
11- In
erica [24]

Answer:    20,736

<u>Step-by-step explanation:</u>

Math and History and Chemistry and Biology and Subjects

  3!     x        4!        x          3!          x        1!          x        4!       = 20,736

5 0
3 years ago
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