The probability is 0.1429.
The probability that the first person chosen is a boy is 5/7. The probability that the second is a boy is 4/6; the third, 3/5; and the fourth, 2/4. Both the numerator and denominator decrease every time, because you lose a boy to choose from and you lose a student to choose from as well. This gives us:
5/7(4/6)(3/5)(2/4) = 120/840 = 0.1429.
Answer:
Step-by-step explanation:
You can solve this in 2 easy steps: 1, multiply 44.55 by .17 (44.55 * .17 = 7.57) then adding the number you get to 44.55 (44.55 + 7.57 = 52.12). Your answer is D.
Answer:
30
Step-by-step explanation:
let EFH = x
Let GFH = y
x + y = 90
x = 2y
Substitute: 2y + y = 90
3y = 90
y = 30
Answer:
Kindly check explanation
Step-by-step explanation:
Given that :
Upper level seat = $25
Mid level seat = $40
Number of tickets to give away is at least 25
Budget constraint = $1000
part A: write a system of two inequalities that describe this situation
Number of tickets constraint:
Upper level + mid level ≥ 25
u + m ≥ 25
Cost constraint :
$25u + $40m ≤ $1000
Part B:
Give away 10 upper level seat tickets and 15 mid level seat tickets
