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user100 [1]
2 years ago
6

How many G3P would be produced if there are 36 Carbon Dioxide that enters the Calvin Cycle?

Biology
1 answer:
hjlf2 years ago
5 0

Answer:

c

Explanation:

Im pretty sure, so sorry if I'm wrong though.

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Can someone answer this
Anuta_ua [19.1K]

Answer:

D. Adenine and Thymine form hydrogen bonds, while cytosine and guanine form covalent bonds.

Explanation:

I majored in Biology

3 0
3 years ago
CAN SOMEONE PLEASE HELP ME!?!?!
Roman55 [17]

Answer:

3) Temperature

4) gill covering opening and closing per minute

5)as temperature rises, the rate of gill covering opening and closing per minute increase until the temperature reaches 27℃ where the rate decreases

Explanation:

4) you can adjust and control the temperature in an experiment

5) you can't control the gill opening and closing rate

4 0
3 years ago
Read 2 more answers
Which type of macromolecule combines with proteins to make compounds such as peptidoglycan and other types of identifying compou
mrs_skeptik [129]

Answer:

Answered below

Explanation:

Pepetidoglycans are the structural polymers which make up the cell walls of most bacteria.

It consists of the macromolecule, glycan chains, which are repeating N-acetylmuramic acid and N-acetylglucosamine residues. These glycan chains combine or cross-link with peptide side chains (proteins) to form a mesh-like layer outside the plasma membrane of most bacteria.

Peptidoglycan is the major structural component and the basic unit of the bacterial cell wall and provides protection to the cytoplasmic membrane, mechanical rigidity and also regulates the passage of fluid, amino acids, sugar and ions, in and out of the cell.

3 0
2 years ago
Convert 86,000 cm to km. Show all of your work.
Dominik [7]
Centimeter = 1/100 of a Meter
Kilometer = 1000 Meters

86,000/100 = 860 Meters
860/1000 = 0.86 Kilometers
3 0
2 years ago
Read 2 more answers
In the parental generation, inbred black and an albino mice parents mate. The resulting F1 mice are black and heterozygous at 2
Semenov [28]

Answer:

12:4:3

Explanation:

Let the lack of color pigmentation which is recessive be aa where AA and Aa allow for color (BB, Bb - black, baby - white).

The F1 parents are BbAa x BbAa

This cross will produce 12/16 blacks, 4/16 albinos and 3/16 white.

7 0
3 years ago
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