Rewrite the product as a power: a^7 *y^7

Mathematics

1 answer:

Umnica [9.8K]3 years ago

5 0

Answer:

ay^7

Step-by-step explanation:

just give me the points.

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Fill in the value of the function, when the input is 2: y = −4 + 2

vovikov84 [41]

Answer:

y = - 6

Step-by-step explanation: You have to substitute 2 for x in order for you to get your solution.

y = - 4x + 2

y = - 4(2) + 2

y = - 8 + 2

y = - 6

Remember, a negative times a positive, becomes a negative

Hope this helps you!!! :)

8 0

3 years ago

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Help you help me. <br><br> Identify each angle relationship. Then find solve for the missing value.

VARVARA [1.3K]

Answer:

Step-by-step explanation:

56 & b are vertical angles so they are the same

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2 years ago

g Gravel is being dumped from a conveyor belt at a rate of 10 ft3/min, and its coarseness is such that it forms a pile in the sh

Maslowich

Answer:

0.3537 feet per minute.

Step-by-step explanation:

Gravel is being dumped from a conveyor belt at a rate of 10 ft3/min. Since we are told that the shape formed is a cone, the rate of change of the volume of the cone.

$\dfrac{dV}{dt}=10$ ft^3/min$

$\text{Volume of a cone}=\dfrac{1}{3}\pi r^2 h$

If the Base Diameter = Height of the Cone

The radius of the Cone = h/2

Therefore,

$\text{Volume of the cone}=\dfrac{\pi h}{3} (\dfrac{h}{2}) ^2 \\V=\dfrac{\pi h^3}{12}$

$\text{Rate of Change of the Volume}, \dfrac{dV}{dt}=\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}$

Therefore: $\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}=10$

We want to determine how fast is the height of the pile is increasing when the pile is 6 feet high.

$When h=6$ feet$\\\dfrac{3\pi *6^2}{12}\dfrac{dh}{dt}=10\\9\pi \dfrac{dh}{dt}=10\\ \dfrac{dh}{dt}= \dfrac{10}{9\pi}\\ \dfrac{dh}{dt}=0.3537$ feet per minute$