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ipn [44]
2 years ago
5

Find the equation of the line described.

Mathematics
2 answers:
elena-14-01-66 [18.8K]2 years ago
8 0

Answer:

y=-\frac{1}{3} x+4

Step-by-step explanation:

The slope of the perpendicular line would be the negative reciprocal of the slope of the first line.

3 would turn into -\frac{1}{3}

You would now have

y=-\frac{1}{3} x+b

To find b, you would plug in the points given to find the y-intercept.

x=6\\y=2

Substitute:

(2)=-\frac{1}{3}(6)+b\\2 = -2+b\\

Add 2 to each side

4=b\\b=4

So the final equation would be

y=-\frac{1}{3} x+4

Lunna [17]2 years ago
5 0

Answer:

y = -1/3x + 4

Step-by-step explanation:

y = 3x +5

current slope m is 3, perpendicular is opposite inverse which is -1/3

Passing through (6,2):

y = mx + b

2 = -1/3(6) + b

2 = -2 + b

b = 4

Use the perpendicular m = -1/3 and b = 4 to form equation of line:

y = mx + b

y = -1/3x + 4

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Answer:

  the point is (3, 3) . . . . . . y = 3

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How do you find the value of c that satisfy the equation:
victus00 [196]

Answer:

The value of c = -0.5∈ (-1,0)

Step-by-step explanation:

<u>Step(i)</u>:-

Given function f(x) = 4x² +4x -3 on the interval [-1 ,0]

<u> Mean Value theorem</u>

Let 'f' be continuous on [a ,b] and differentiable on (a ,b). The there exists a Point 'c' in (a ,b) such that

f^{l} (c)  = \frac{f(b) -f(a)}{b-a}

<u>Step(ii):</u>-

Given  f(x) = 4x² +4x -3 …(i)

Differentiating equation (i) with respective to 'x'

          f¹(x) = 4(2x) +4(1) = 8x+4

<u>Step(iii)</u>:-

By using mean value theorem

f^{l} (c)  = \frac{f(0) -f(-1)}{0-(-1)}

8c+4 = \frac{-3-(4(-1)^2+4(-1)-3)}{0-(-1)}

8c+4 = -3-(-3)

8c+4 = 0

8c = -4

c = \frac{-4}{8} = \frac{-1}{2} = -0.5

c ∈ (-1,0)

<u>Conclusion</u>:-

The value of c = -0.5∈ (-1,0)

         

<u></u>

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