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3 years ago

Why do you think people cannot drink seawater?

Chemistry

1 answer:

Oksanka [162]3 years ago

5 0

Answer:

Its contaminated

Explanation:

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Choose all the answers that apply.

zmey [24]

Calcium is a non metal

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3 years ago

Read 2 more answers

How many electrons will strontium lose to satisfy the octet rule?

Law Incorporation [45]

Answer:

Two Electrons.

Explanation:

Strontium is the atom with atomic number 38, and electron configuration is [Kr] 5S^2 which mean just two electrons more than Krypton which one of the Noble gases.

8 0

3 years ago

A solution with a pH value between 1 and 6

lozanna [386]

Answer:

One possible answer could be lemon juice

Explanation:

We had to do a water test, and I was looking up what pH levels were. Then I learned about it in school, so I know a thing or two about it :)

Possible other answers include stomach acid and cola.

Hope this helps!!

4 0

3 years ago

The human body has several major systems. Most body systems have multiple functions. Which of the following is NOT a major funct

tensa zangetsu [6.8K]

Answer:D

Explanation:

i got it right LOL

8 0

3 years ago

It is expected that a chemical reaction will occur when copper metal is combined with aqueous zinc sulfate. Explain why there wi

REY [17]

Answer:

$E_{cell}$ = +ve, reaction is spontaneous

$E_{cell}$ = -ve, reaction is non spontaneous

$E_{cell}$ = 0, reaction is in equilibrium

Case 1: when copper metal is combined with aqueous zinc sulfate.

$Cu+ZnSO_4\rightarrow Zn+CuSO_4$

Here copper is undergoing oxidation ad thus acts as anode and zinc is undergoing reduction , thus acts as cathode.

$E^o_{cell}$ = standard electrode potential = $E^0_{cathode}- E^0_{anode}$

Where both $E^0$ are standard reduction potentials.

$E^0_{[Cu^{2+}/Cu]}= +0.34V$

$E^0_{[Zn^{2+}/Zn]}= -0.76V$

$E^0=E^0_{[Zn^{2+}/Zn]}- E^0_{[Cu^{2+}/Cu]}$

$E^0=-0.76-(+0.34)=-1.10V$

Thus as $E_{cell}$ is negative , the reaction is non spontaneous.

Case 2: when zinc metal and aqueous copper sulfate solution are combined.

$Zn+CuSO_4\rightarrow Cu+ZnSO_4$

Here zinc is undergoing oxidation ad thus acts as anode and copper is undergoing reduction , thus acts as cathode.

$E^o_{cell}$ = standard electrode potential = $E^0_{cathode}- E^0_{anode}$

Where both $E^0$ are standard reduction potentials.

$E^0_{[Cu^{2+}/Cu]}= +0.34V$

$E^0_{[Zn^{2+}/Zn]}= -0.76V$

$E^0=E^0_{[Cu^{2+}/Cu]}- E^0_{[Zn^{2+}/Zn]}$

$E^0=+0.34-(-0.76)=+1.10V$

Thus as $E_{cell}$ is positive , the reaction is spontaneous.

3 0

4 years ago