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Furkat [3]
3 years ago
14

A 36.75 kg boulder is rolling down a hill. If, at one moment, the boulder has a momentum of 241.5 kg. m/s, what is its

Physics
1 answer:
Lady_Fox [76]3 years ago
3 0

Answer:

6.571428571m/s

Explanation:

The momentum of an object is basically a measure of its motion, and it takes both mass and the velocity an object is travelling at into account.

Momentum = mass x velocity

<em>(sub in values from question)</em>

241.5=36.75v

v=6.571428571m/s

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the velocity of a car traveling in the positive direction decreases from 32 m/s to 24 m/s in 4 seconds. what is the average acce
anastassius [24]

Answer:

a=-2m/sec^2

Negative sign shows that velocity of the car is decreases at a constant rate

Explanation:

We have given velocity of the car is decreases from 32 m /sec to 24 m/sec in 4 second

So initial velocity of the car u = 32 m /sec

And finally car reaches to a velocity of 24 m/sec

Time taken to change in velocity = 4 sec

So final velocity v = 24 m/sec

From first equation of motion v = u+at

So 24=32+a\times 4

a=-2m/sec^2

Negative sign shows that velocity of the car is decreases at a constant rate

6 0
3 years ago
What is a fact about incline planes?
SVETLANKA909090 [29]
They are incline hope this helps!
8 0
3 years ago
Write two examples of machine which changes the direction of force​
Ostrovityanka [42]

Answer:

Washign machine and swingset

Explanation:

4 0
2 years ago
How much heat is evolved when 1234 g of water condenses to a liquid at 100.°c?
lbvjy [14]
During the phase transition vapour --> liquid water, the temperature of the water does not change; the molecules of water release heat and the amounf of heat released is equal to
Q=mL_e
where
m is the mass of the water
L_e is the latent heat of evaporation.

For water, the latent heat of evaporation is L=2257 kJ/kg, while the mass of the water is
m=1234 g=1.234 kg

so, the amount of heat released in the process is
Q=mL_e = (1.234 kg)(2257 kJ/kg)=2785 kJ
6 0
3 years ago
a person dives off the edge of aa cliff 33m above the surface of the sea. assuming that air resistance is negligible, how long d
USPshnik [31]

Answer:

The time is t = 2.595 \  s

The speed is v = 25.43 \ m/s

Explanation:

From the question we are told that

    The height of the cliff is  h =  33 \  m

 Generally from kinematic equation we have that

       h  =  ut + \frac{1}{2} gt^2

before the jump the persons initial velocity is  u =  0 m/s

 So

        33   =  0 * t + \frac{1}{2} 9.8 * t^2

=>      t = 2.595 \  s

Generally from kinematic equation

     v= u + gt

=>  v= 0 + 9.8 * 2.595

=>  v = 25.43 \ m/s

3 0
3 years ago
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