Answer:
Approximately
(assuming that
.)
Explanation:
Let
denote the force that this spring exerts on the object. Let
denote the displacement of this spring from the equilibrium position.
By Hooke's Law, the spring constant
of this spring would ensure that
.
Note that the mass of the object attached to this spring is
. Thus, the weight of this object would be
.
Assuming that this object is not moving, the spring would need to exert an upward force of the same magnitude on the object. Thus,
.
The spring in this question was stretched downward from its equilibrium by:
.
(Note that
is negative since this displacement points downwards.)
Rearrange Hooke's Law to find
in terms of
and
:
.
It would mostly depend on its weight
<h3>Answer</h3>
1104 km/hour
<h3>Explanation</h3>
Distance between Dallas Texas to New York = 2760 km
Time the plane took from Dallas to New York = 2 hours
Time the plane took from New York back to Dallas = 2.5 hours
Formula to use
<h3>distance = speed x time </h3>
Speed the plane took from Dallas to New York
2760 = 2 x speed
speed = 2760 / 2
= 1380 km/hour
Speed the plane took from New York to Dallas (ROUND TRIP)
2760 = 2.5 x speed
speed = 2760 / 2.5
= 1104 km/hour
Answer:
(a) 62.69 nJ/m^3
(b) 1015.22 μJ/m^3
Explanation:
Electric field, E = 119 V/m
Magnetic field, B = 5.050 x 10^-5 T
(a) Energy density of electric field = 
= 6.269 x 10^-8 J/m^3 = 62.69 nJ/m^3
(b) energy density of magnetic field = 

= 1.01522 x 10^-3 J/m^3 = 1015.22 μJ/m^3