The Factorization of 121b⁴ − 49 is (11b^2 + 7)(11b^2 - 7).
The equation 121b⁴ − 49
To find the Factorization of 121b⁴ − 49.
<h3>
What is the factor of a^2-b^2?</h3>
The factor of a^2-b^2 is (a+b)(a-b)
We have write the given equation in the form of a^2-b^2

Therefore the factor of the 121b^4 − 49 is (11b^2 + 7)(11b^2 - 7).
To learn more about the factor visit:
brainly.com/question/25829061
Answer:
odd numbers
Step-by-step explanation:
4 - 7 is 3, 7 - 12 is 5, 12 - 19 is 7, 19 to 28 is 9
So just keep counting
Answer:
4. answer is -48xy
5. answer is 1
Step-by-step explanation:
4. -3/4*-8y*4/3*6x*-1
=6y*4/3*6x*-1
=8x*6x*-1
-48xy
5.
-13.6/x=-13.6/1
If the numerators are the same, the denominators have to too.