Answer:
x= -3 and y = 6
Step-by-step explanation:
so basically what you are trying to do is reduce into finding x and y
what you do is you want to find a number to multiply one of the equations in order to get the same x or y value does not matter which
so,...
we can do
either 20x or 15y
we will go with the smallest 15y
so for both equations multiply the whole thing by 5 for the first equation and by 3 for the second
5 x 5x+3y=3 --> 1
3 x 4x+5y=18 --> 2
we then get
25x+15y = 15 -->1
12x + 15y = 54 -->2
then now that you have the same Y values you can subtract ! which cancels out both the 15y
25x+15y = 15 -->1
- 12x + 15y = 54 -->2
13x =-39
so now x=-3 and all you have to do with x = -3 is sub this into either one of the equations that you started with !
x = -3
5(-3) +3y =3
-15 + 3y = 3
3y = 3+15
3y=18
y = 6!
Answer:
The intermediate step are;
1) Separate the constants from the terms in x² and x
2) Divide the equation by the coefficient of x²
3) Add the constants that makes the expression in x² and x a perfect square and factorize the expression
Step-by-step explanation:
The function given in the question is 6·x² + 48·x + 207 = 15
The intermediate steps in the to express the given function in the form (x + a)² = b are found as follows;
6·x² + 48·x + 207 = 15
We get
1) Subtract 207 from both sides gives 6·x² + 48·x = 15 - 207 = -192
6·x² + 48·x = -192
2) Dividing by 6 x² + 8·x = -32
3) Add the constant that completes the square to both sides
x² + 8·x + 16 = -32 +16 = -16
x² + 8·x + 16 = -16
4) Factorize (x + 4)² = -16
5) Compare (x + 4)² = -16 which is in the form (x + a)² = b
Answer:
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