4 m 3m 6 m 8 m UE 3 m Your answer
1 answer:
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The complete question in the attached figure
Part a)
we know that
ABC is a right triangle
∠ACB=45°
AC=hypotenuse------> 6√2 cm
sin 45=AB/AC-----> AB=AC*sin 45----> AB=6√2*√2/2----> AB=6 cm
the answer part a) is
AB=6 cm
Part b)
we know that
volume of the pyramid=(1/3)*Area of the base*height
area of the base=50 cm²
height=6 cm
so
volume of the pyramid=(1/3)*50*6----> 100 cm³
the answer part b) is
100 cm³
Part a)
we know that
ABC is a right triangle
∠ACB=45°
AC=hypotenuse------> 6√2 cm
sin 45=AB/AC-----> AB=AC*sin 45----> AB=6√2*√2/2----> AB=6 cm
the answer part a) is
AB=6 cm
Part b)
we know that
volume of the pyramid=(1/3)*Area of the base*height
area of the base=50 cm²
height=6 cm
so
volume of the pyramid=(1/3)*50*6----> 100 cm³
the answer part b) is
100 cm³
Considering the given angle and the given formula, it is found that the percentage error for an angle of 0.02 radians is of 0.0067%.
<h3>What is the percentage angle for an angle?</h3>For an angle , it is given by the following formula:
In this problem, the angle is of , hence:
The percentage error for an angle of 0.02 radians is of 0.0067%.
More can be learned about percent error at brainly.com/question/25224978