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Kisachek [45]
3 years ago
7

Determine the 15th term of the arithmetic sequence -9, -6, -3, 0, 3....

Mathematics
1 answer:
Alborosie3 years ago
8 0

Answer:

33

Step-by-step explanation:

-9, -6, -3, 0, 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33. 33 is the answer because it is the 15th number in the pattern. The numbers are going up by 3. I hope this is right and helps!

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I'm so sorry I can't help but you can try and use math-way to answer anyquestions regarding equations and such!

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The cost of one hamburger is $3.95.

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15.80/4=3.95

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40/6 as a mixed number and in simpliest form
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5-2.1=? 5-2.17=? 5-2 7/8 solve make sure to re-check your self before answering or no forty points
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3 years ago
According to a marketing research study, American teenagers watched 14.8 hours of social media posts per month last year, on ave
ki77a [65]

Answer:

The value of test statistics is 1.06.

Step-by-step explanation:

We are given that according to a marketing research study, American teenagers watched 14.8 hours of social media posts per month last year, on average. A random sample of 11 American teenagers was surveyed and the mean amount of time per month each teenager watched social media posts was 15.6. This data has a sample standard deviation of 2.5.

We have to test if the mean amount of time American teenagers watch social media posts per month is greater than the mean amount of time last year or not.

Let, NULL HYPOTHESIS, H_0 : \mu = 14.8 hours  {means that the mean amount of time American teenagers watch social media posts per month is same as the mean amount of time last year}

ALTERNATE HYPOTHESIS, H_1 : \mu > 14.8 hours  {means that the mean amount of time American teenagers watch social media posts per month is greater than the mean amount of time last year}

The test statistics that will be used here is One-sample t-test;

             T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean amount of time per month each teenager watched social media posts = 15.6 hours

             s = sample standard deviation = 2.5 hours

             n = sample of teenagers = 11

So, <u>test statistics</u> =  \frac{15.6 - 14.8}{\frac{2.5}{\sqrt{11} } } ~ t_1_0

                            = 1.06

Hence, the value of test statistics is 1.06.

5 0
3 years ago
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