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djverab [1.8K]
3 years ago
5

Also what happens if you decrease NOCL

Chemistry
1 answer:
Paladinen [302]3 years ago
6 0

Answer:

el que paso del one jhaulio

Explanation:

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Chemistry help please
Galina-37 [17]

Answer:

The reaction isn't yet at equilibrium. The overall reaction will continue to move in the direction of the products.

Assumption: this system is currently at \rm 900^{\circ}C.

Explanation:

One way to tell whether a system is at its equilibrium is to compare its reaction quotient Q with the equilibrium constant K_c of the reaction.

The equation for Q is quite similar to that for K_c. The difference between the two is that K_c requires equilibrium concentrations, while Q can be calculated even when the system is on its way to equilibrium.

For this reaction,

\displaystyle Q = \rm \frac{[CS_2]\cdot [H_2]^{4}}{[CH_4]\cdot [H_2S]^{2}}.

Given these concentrations,

\displaystyle Q = \rm \frac{[CS_2]\cdot [H_2]^{4}}{[CH_4]\cdot [H_2S]^{2}} =\frac{1.51\times (1.08)^{4}}{1.15\times (1.20)^{2}} \approx 1.72.

The question states that at \rm 900^{\circ}C, K_c = 3.59. Assume that currently this system is also at \rm 900^{\circ}C. (The two temperatures need to be the same since the value of K_c depends on the temperature.)

It turns out that Q = K_c. What does this mean?

  • First, the system isn't at equilibrium.
  • Second, if there's no external changes, the system will continue to move towards the equilibrium. Temperature might change. However, eventually Q will be equal to K_c, and the system will achieve equilibrium.

In which direction will the system move? At this moment, Q < K_c. As time proceeds, the value of Q will increase so that it could become equal to K_c. Recall that Q is fraction.  

\displaystyle Q = \rm \frac{[CS_2]\cdot [H_2]^{4}}{[CH_4]\cdot [H_2S]^{2}}

When the value of Q increases, either its numerator becomes larger or its denominator becomes smaller, or both will happen at the same time. However,

  • Concentrations on the numerator of Q are those of the products;
  • Concentrations on the denominator of Q are those of the reactants.

As time proceeds,

  • the concentration of the products will increase, while
  • the concentration of the reactants will decrease.

In other words, the equilibrium will move towards the products.

3 0
4 years ago
a weight loss supplement i advertised in several popular beauty and and fashion magazines the advertisements claim that the supp
inessss [21]

to provide scientific evidence and results

8 0
3 years ago
What will happen if you weighed out a quantity of beans
Ostrovityanka [42]

Answer:

When we weigh beans in this mass ratio, we must obtain the same number of beans.Explanation:

Nothing will happen

3 0
3 years ago
Calculate the maximum concentration (in m) of silver ions (ag+) in a solution that contains 0.025 m of co32-. the ksp of ag2co3
Helen [10]
Equilibrium equation is

<span>Ag2CO3(s) <---> 2 Ag+(aq) + CO32-(aq) </span>

<span>From the reaction equation above, the formula for Ksp: </span>

<span>Ksp = [Ag+]^2 [CO32-] = 8.1 x 10^-12 </span>
<span>You know  [CO32-], so you can solve for [Ag+] as: </span>
<span>(8.1 x 10^-12) = [Ag+]^2 (0.025) </span>
<span>[Ag+]^2 = 3.24 x 10^-10 </span>
<span>[Ag+] = 1.8 x 10^-5 M </span>
5 0
3 years ago
Select the statements that are true about electronegativity between elements,
s2008m [1.1K]

Answer:

a

Explanation:

if the difference is over 1.7, an ionic bond will form

4 0
3 years ago
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