JJ Thomson proved John Dalton's theory wrong, as Thomson discovered the electron. This showed that there were particles that were smaller than an atom, despite Dalton claiming that the atom is the smallest unit of matter.
Answer:
Dynamic equilibrium occurs when the rate of the forward reaction equals the rate of the reverse reaction:
Explanation:
Reaction quotient is the ratio of product of concentrations of products to product of concentrations of reactants at any time.
The same ratio at equilibrium (when rate of forward reaction becomes equal to rate of backward reaction) is equilibrium constant.
when Q < Kc, a forward reaction is favored.
When when Q > Kc, a backward or reverse reaction is favored
So the first statement that
a) A reaction quotient (Q) larger than the equilibrium constant (K) means that the reaction will favor the production of more products: false
b) No the rate of forward and backward reaction are equal.
c) c. Dynamic equilibrium occurs when the rate of the forward reaction equals the rate of the reverse reaction: True
d) Dynamic equilibrium indicates that the amount of reactants and products are equal: This could be static equilibrium but not dynamic.
Answer:
285g of fluorine
Explanation:
To solve this problem we need to find the mass of Freon in grams. Then, with its molar mass we can find moles of freon and, as 1 mole of Freon, CCl₂F₂, contains 2 moles of fluorine, we can find moles of fluorine and its mass:
<em>Mass Freon:</em>
<em>2.00lbs * (454g / 1lb) = </em>908g of Freon
<em>Moles freon -Molar mass: 120.91g/mol- and moles of fluorine:</em>
908g of Freon * (1mol / 120.91g) =
7.5 moles of freon * (2moles Fluorine / mole Freon): 15 moles of fluorine
<em>Mass fluorine -Atomic mass: 19g/mol-:</em>
15 moles F * (19g / mol) =
<h3>285g of fluorine</h3>
Use the universal gas formula
PV=nRT
where
P=pressure ( 0.980 atm)
V=volume (L)
T=temperature ( 23 ° C = 23+273.15 = 296.15 ° K)
n=number of moles of ideal gas (0.485 mol)
R=universal gas constant = 0.08205 L atm / (mol·K)
Substitute values,
Volume, V (in litres)
=nRT/P
=0.485*0.08205*296.15/0.980
= 12.0256 L
= 12.0 L (to three significant figures)
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