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Alex Ar [27]
3 years ago
7

HELP HELP HELP HELP ME!!!!!!!!!!!!!!!

Mathematics
1 answer:
leonid [27]3 years ago
4 0

Answer:

l=\frac{A-\frac{1}{2} \pi w^2}{2w}

Step-by-step explanation:

We essentially need to solve for l; in other words, we must isolate it to one side.

First, notice that the term \frac{1}{2} \pi w^2 doesn't have any l terms in it, so we can just move this to the left side by subtracting both sides by \frac{1}{2} \pi w^2:

A - \frac{1}{2} \pi w^2 = 2lw

Now, the right side has 2lw, so we must divide both sides by 2w to isolate l:

l=\frac{A-\frac{1}{2} \pi w^2}{2w}

<em>~ an aesthetics lover</em>

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Answer:

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8 0
3 years ago
Attempted but just couldnt understand (25Points)​
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Answer:

a) Function:Yes

b) Domain: -5\:

c) Range:  -5\le y\le 3

Step-by-step explanation:

The given graph passes vertical line test hence it is a function

The given function has x-intercepts at x=-4.5, x=-1,x=3.5

We can therefore write this function in factored form as y=a(2x+9)(x+1)(2x-7)

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-2=-63a

a=\frac{2}{63}

The required function is

y=\frac{2}{63}(2x+9)(x+1)(2x-7)

b) The domain refers to all values of x for which this function is defined.

The domain from the graph is -5\: because there are holes at the end of the graph.

c) The range is the value of y for which x is defined or the graph exists.

From the graph the range is -5\le y\le 3

5 0
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Step-by-step explanation:

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Step-by-step explanation:

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