Hello :
<span>3y = x + 6 ...(1)
y – x = 3...(2)
by (2) : y = x+3...(*)
subsct in (1) :
3(x+3) = x+6
3x-x= -9+6
2x= -3
x=-3/2
subsct in (*) : y =-3/2 +3 =3/2</span>
Explanation:
Consider ...
x/a = b/c . . . . . find x
Multiplying by the denominator under x gives ...
x = ab/c . . . . the value of the unknown.
____
In the case where the unknown is in the denominator, you can invert the ratios and solve as above:
a/x = c/b . . . . . note that x is in the denominator
x/a = b/c . . . . . equivalent equation, solve as above
So, first off it would help if you could define the terms irrational number and integer. Well, an irrational number is basically any real number that can't be expressed as a ratio of integers. They also cannot be represented by terminating or continuing decimals. And an integer is pretty much any number that cannot be written as a fraction or decimal, such as -2, 13, 257. It is not 2 and 1/2, or 4.75. Those would not be integers. Do you think you can figure out the difference?
All you have to do is divde hope this helps thank ylu
Answer: D- 6 times the eighth root of x to the fifth power.
Step-by-step explanation:
Bring denominator e as the small number in front of root.
Bring x into the root and the numerator as the power x is raised too.
Have it all times 6.
