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inn [45]
3 years ago
5

Find the missing side length.

Mathematics
1 answer:
nordsb [41]3 years ago
4 0
12 yd

You can use what you are provided with the 7 day and 5 yd which equal the side that is missing

7+5 =12
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If $4500 earns $120 simple interest at a flat rate of 2% p.a., calculate the duration of the investment.
Nimfa-mama [501]

Answer:

1.33 years.

Step-by-step explanation:

I=PRT

120=4500(0.02)T

120/90=T

T=4/3

4 0
3 years ago
Write the equation of a line that includes the point (22, 12) and
STatiana [176]

Let's start with y = 4x + b (since 4 is the slope);

We need to find what number should be put instead of b;

Then, let's see what needs to be done;

Plug in the y and x values from the coordinate (22,12) into y=4x+b;

12 = 4(22) + b

Solve;

12 = 88 + b

12 - 88 = b

b = -76

Remember the equation y = 4x + b? Put the -76 instead of b:

y = 4x + -76

or: y = 4x - 76

That is the equation.

To make it standard form, put x and y both in the left side, with x first then y:

-4x + y = -76

^^Answer!

7 0
3 years ago
To eliminate the y terms and solve for x in the fewest steps, by which constants should the equation need multiplied by before a
ivanzaharov [21]
A. Multiplied by 2 for the first then for the second multiply by three.

Explanation: the equations already have opposite signs for y so reversing the signs would be counterproductive. (Eliminates B and D) and the easiest way is to get the numbers before the Y variable to be the same. The top by 2 and bottom by 3 would do that, leaving only A.
3 0
2 years ago
What is the constant of proportionality in the equation 3y=2x
Inessa05 [86]

Answer:

2/3

Step-by-step explanation:

3y = 2x

Divide each side by 3

3y/3 = 2x/3

y = 2/3 x

The  direct variation relationship is

y = kx

In this case k = 2/3

4 0
2 years ago
Read 2 more answers
What is the Laplace Transform of 7t^3 using the definition (and not the shortcut method)
Leokris [45]

Answer:

Step-by-step explanation:

By definition of Laplace transform we have

L{f(t)} = L{{f(t)}}=\int_{0}^{\infty }e^{-st}f(t)dt\\\\Given\\f(t)=7t^{3}\\\\\therefore L[7t^{3}]=\int_{0}^{\infty }e^{-st}7t^{3}dt\\\\

Now to solve the integral on the right hand side we shall use Integration by parts Taking 7t^{3} as first function thus we have

\int_{0}^{\infty }e^{-st}7t^{3}dt=7\int_{0}^{\infty }e^{-st}t^{3}dt\\\\= [t^3\int e^{-st} ]_{0}^{\infty}-\int_{0}^{\infty }[(3t^2)\int e^{-st}dt]dt\\\\=0-\int_{0}^{\infty }\frac{3t^{2}}{-s}e^{-st}dt\\\\=\int_{0}^{\infty }\frac{3t^{2}}{s}e^{-st}dt\\\\

Again repeating the same procedure we get

=0-\int_{0}^{\infty }\frac{3t^{2}}{-s}e^{-st}dt\\\\=\int_{0}^{\infty }\frac{3t^{2}}{s}e^{-st}dt\\\\\int_{0}^{\infty }\frac{3t^{2}}{s}e^{-st}dt= \frac{3}{s}[t^2\int e^{-st} ]_{0}^{\infty}-\int_{0}^{\infty }[(t^2)\int e^{-st}dt]dt\\\\=\frac{3}{s}[0-\int_{0}^{\infty }\frac{2t^{1}}{-s}e^{-st}dt]\\\\=\frac{3\times 2}{s^{2}}[\int_{0}^{\infty }te^{-st}dt]\\\\

Again repeating the same procedure we get

\frac{3\times 2}{s^2}[\int_{0}^{\infty }te^{-st}dt]= \frac{3\times 2}{s^{2}}[t\int e^{-st} ]_{0}^{\infty}-\int_{0}^{\infty }[(t)\int e^{-st}dt]dt\\\\=\frac{3\times 2}{s^2}[0-\int_{0}^{\infty }\frac{1}{-s}e^{-st}dt]\\\\=\frac{3\times 2}{s^{3}}[\int_{0}^{\infty }e^{-st}dt]\\\\

Now solving this integral we have

\int_{0}^{\infty }e^{-st}dt=\frac{1}{-s}[\frac{1}{e^\infty }-\frac{1}{1}]\\\\\int_{0}^{\infty }e^{-st}dt=\frac{1}{s}

Thus we have

L[7t^{3}]=\frac{7\times 3\times 2}{s^4}

where s is any complex parameter

5 0
2 years ago
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