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amid [387]
3 years ago
9

find the equation of the straight line which has a gradient of 3 and passes through the point (-1, 3)

Mathematics
1 answer:
iogann1982 [59]3 years ago
8 0

Answer:

y=3x+6

Step-by-step explanation: 3=3(-1)+b

                                             3=-3+b

                                             +3  +3

                                              6=b

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Explain how to do this
patriot [66]
The answer is C because you divide the P so you get KP=AR then you finish the rest
5 0
3 years ago
Read 2 more answers
Type the correct answer in each box. Use numerals instead of words.
lubasha [3.4K]

Answer:

System A has 4 real solutions.

System B has 0 real solutions.

System C has 2 real solutions

Step-by-step explanation:

System A:

x^2 + y^2 = 17   eq(1)

y = -1/2x            eq(2)

Putting value of y in eq(1)

x^2 +(-1/2x)^2 = 17

x^2 + 1/4x^2 = 17

5x^2/4 -17 =0

Using quadratic formula:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

a = 5/4, b =0 and c = -17

x=\frac{-(0)\pm\sqrt{(0)^2-4(5/4)(-17)}}{2(5/4)}\\x=\frac{0\pm\sqrt{85}}{5/2}\\x=\frac{\pm\sqrt{85}}{5/2}\\x=\frac{\pm2\sqrt{85}}{5}

Finding value of y:

y = -1/2x

y=-1/2(\frac{\pm2\sqrt{85}}{5})

y=\frac{\pm\sqrt{85}}{5}

System A has 4 real solutions.

System B

y = x^2 -7x + 10    eq(1)

y = -6x + 5            eq(2)

Putting value of y of eq(2) in eq(1)

-6x + 5 = x^2 -7x + 10

=> x^2 -7x +6x +10 -5 = 0

x^2 -x +5 = 0

Using quadratic formula:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

a= 1, b =-1 and c =5

x=\frac{-(-1)\pm\sqrt{(-1)^2-4(1)(5)}}{2(1)}\\x=\frac{1\pm\sqrt{1-20}}{2}\\x=\frac{1\pm\sqrt{-19}}{2}\\x=\frac{1\pm\sqrt{19}i}{2}

Finding value of y:

y = -6x + 5

y = -6(\frac{1\pm\sqrt{19}i}{2})+5

Since terms containing i are complex numbers, so System B has no real solutions.

System B has 0 real solutions.

System C

y = -2x^2 + 9    eq(1)

8x - y = -17        eq(2)

Putting value of y in eq(2)

8x - (-2x^2+9) = -17

8x +2x^2-9 +17 = 0

2x^2 + 8x + 8 = 0

2x^2 +4x + 4x + 8 = 0

2x (x+2) +4 (x+2) = 0

(x+2)(2x+4) =0

x+2 = 0 and 2x + 4 =0

x = -2 and 2x = -4

x =-2 and x = -2

So, x = -2

Now, finding value of y:

8x - y = -17    

8(-2) - y = -17    

-16 -y = -17

-y = -17 + 16

-y = -1

y = 1

So, x= -2 and y = 1

System C has 2 real solutions

4 0
4 years ago
Read 2 more answers
4 cot theta<br>=<br>tan theta<br>how do I I find the value of quadrant?​
Ray Of Light [21]

Answer:

4cotα=tanα

4(1/tanα)=tanα

(4/tanα)=tanα

cross multiply

=> 4=tan²α

√4=√tan²α

±2=tanα

α=arc( tan) |2|

α=63.4° ( in first quadrant)

and

α=180+63.4=243.4 in the third quadrant

since we also found a negative answer( i.e –2) then α also lies in quadrants where it gives a negative value(i.e second and fourth quadrants)

α=180–63.4=116.6° in the second quadrant

α=360–63.4=296.6 in the fourth quadrant

therefore theta( in my case, alpha) lies in all four quadrants and is equal to:

α=63.4°,243.4°,116.6°and 296.6°

5 0
3 years ago
Help please
Len [333]

Answer:

Ques 1)  1440°

Ques 2) 4000

Ques 3) 33

Step-by-step explanation:

Ques 1)

The sum of the measures of the angles in degrees of a polygon with 'n' sides is given by: 180×(n - 2).

Now we have to find the sum of the measures the angles of a polygon with 10 sides.

i.e. n=10

Hence the value of the expression 180×(n-2) when n=10 is given by:

180×(10-2)=180×8=1440.

Hence, the sum of measure of the angles of a polygon with 10 sides is: 1440°.

Ques 2)

The Expression 500v gives the number of points a player earns for completing v voyages in video game.

We are asked to find the number of points earned for completing 8 voyages.

i.e. v=8 the value of 500v will be 500×8=4000.

Hence, 4000 points are earned for completing 8 voyages.

Ques 3)

we have to find the value of the question as given in the figure:

7x+y+16 for x=2 and y=3.

Hence, we find the value of the expression:

7×2+3+16=33.

Hence, the value of the expression is 33.




8 0
3 years ago
Help me please and thanks
Arturiano [62]

This is the answer its easy just simplify the inequality

3 0
4 years ago
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