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Bogdan [553]
3 years ago
15

A rectangular lot that measures 150 ft by 200 ft is completely fenced. What is the approximate length, in feet, of the fence?

Mathematics
1 answer:
Ivenika [448]3 years ago
3 0
300,000 because you have to just multiply 150 by 200
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Lincoln Middle School has a student body of 5 ^5 students. Each class has approximately 5 ^2 students. How many classes does the
Tamiku [17]

There are 5^5 students on the school and 5^2 students per class.


So, think:


1 class ----------- 5^2 students

x classes ---------- 5^5 students


Multiply:


1 . 5^5 = x . 5^2

So,


5^5 = x.5^2

x = \frac{5^5}{5^2}

x = 5^{5-2}

x = 5^3

x = 125


There are 125 classes.

4 0
2 years ago
Read 2 more answers
The ratio of the dimensions of a rectangular patio are 4:7. if the shorter
Cerrena [4.2K]

If the ratio of the dimensions is 4:7 and the shorter dimension is 10ft, we know that the 10ft corresponds to the 4 in this scenario. We can set up the equation as follows:

\frac{4}{7} =\frac{10}{x}

You have to multiply by 2.5 to get from 4 to 10. And since we want to make sure we are maintaining the ratio, we have to multiply the denominator, 7, by 2.5 as well.

\frac{4}{7}*\frac{2.5}{2.5}=\frac{10}{17.5}

This means your shorter side has a length of 10ft and your longer side has a length of 17.5ft.

AREA

The formula for the area of a rectangle is: w*l

So we can plug our dimensions into the formula: 10*17.5=175

So 175 is our area. But we can't forget about units! Since this is area and we multiplied our units together, our units would be squared. That means our answer is <u>175 square feet</u>.

PERIMETER

The formula for the perimeter of a rectangle is: 2(w+l)

We can plug our dimensions into the formula: 2(10+17.5)=55

So 55 is our perimeter. Of course, we can't forget about our units. Because this is perimeter, we only added our units together, so they don't change. That means our answer is <u>55 feet</u>.

4 0
2 years ago
If 5 tractors can plow a field in 4 hours, how many hours will it take 3 tractors to plow the field?
Mrac [35]

The number of hours required for 3 tractors to plow the field is 2.4 hours

<em><u>Solution:</u></em>

Given that 5 tractors can plow a field in 4 hours

We have to find out number of hours required for 3 tractors to plow the field

5 tractors can plow a field in 4 hours, So time taken for 1 tractor

\text{ time taken for 1 tractor } = \frac{\text{ time taken for 5 tractor}}{5}

\text{ time taken for 1 tractor } = \frac{4}{5} \text{ hours }

<em><u>So time taken for 3 tractors is given as:</u></em>

time taken for 3 tractor = time taken for 1 tractor x 3

\text{ time taken for 3 tractor} = \frac{4}{5} \times 3 = \frac{12}{5}

\rightarrow \frac{12}{5} = 2.4

So number of hours required for 3 tractors to plow the field is 2.4 hours

3 0
3 years ago
BRAINLIEST ✨
inna [77]

<em>Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.</em>

<em>Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, or</em>

<em>Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, or</em>

<em>Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, or</em>

<em>Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.</em>

<em>Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.</em>

<em>Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.</em>

<em>Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.Check: (2 + 2/3), (2 + 3*2/3), (2 + 6*2/3)</em>

<em>Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.Check: (2 + 2/3), (2 + 3*2/3), (2 + 6*2/3)= 8/3, 4, 6</em>

<em>Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.Check: (2 + 2/3), (2 + 3*2/3), (2 + 6*2/3)= 8/3, 4, 6Common ratio: 4/(8/3) = 3/2 same as 6/4 = 3/2. Correct.</em>

Step-by-step explanation:

Am I right? just commet if I'm wrong

then <em>TANKYOU>^_^<!</em>

7 0
2 years ago
Whats the difference between a $20,000 and a $50,000 annual salary over a lifetime?
laiz [17]
The difference between the two salaries is $30,000
50,000
-20,000
__________
30,000
7 0
3 years ago
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