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Sidana [21]
4 years ago
14

Complete the work to solve for y:

Mathematics
2 answers:
dmitriy555 [2]4 years ago
7 0

actuallly its 11/2 because i did it on edge and it was right your welcome. mark the brainlist please

labwork [276]4 years ago
3 0

Answer:

he was in a way where I can see and the other ones but he said that u are so happy that I was like I like to meet I just dont

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What is the average rate of change of f(x), represented by the table of values, over the interval [-2, 3]?
aksik [14]
Average rate of change = (f(b) - f(a))/(b - a) = (f(3) - f(-2))/(3 - (-2)) = (5 - 2.5)/(3 + 2) = 2.5/5 = 0.5
5 0
4 years ago
Read 2 more answers
What is the reciprocal of -9/11 A -11/9 B 11/9 C /911 D -9/11 plz help
alexgriva [62]
It's is A -11/9 hope this helps
3 0
3 years ago
Read 2 more answers
in a given year, the rate of flu infection for the general public was 8.3%. And sample of 200 people who receive the flu vaccine
makkiz [27]

Answer:

\fbox{\begin{minipage}{10em}Option A is correct\end{minipage}}

Step-by-step explanation:

<em>Step 1: Define significance level</em>

In this hypothesis testing problem, significance levels α is selected: 0.05, the associated z-value from Laplace table:

Φ(z) = α - 0.5 = 0.05 - 0.5 = -0.45

=> z = -1.645

<em>Step 2: Define null hypothesis (</em>H_{0}<em>) and alternative hypothesis (</em>H_{1}<em>)</em>

H_{0} : rate of flu infection p = 8.3% or 8.3/100 = 0.083

H_{1} : rate of flu infection p < 8.3% or 8.3/100 = 0.083

<em>Step 3: Apply the formula to check test statistic:</em>

K = \frac{f - p}{\sqrt{p(1 - p)} } * \sqrt{n}

with f is actual sampling percent, p is rate of flu infection of H_{0}, n is number of samples.

The null hypothesis will be rejected if K < z

<em>Step 4: Calculate the value of K and compare with </em>z

K = \frac{(\frac{3.5}{100})  - 0.083}{\sqrt{0.083(1 - 0.083)} } * \sqrt{200} = -2.46  

We have -2.46 < -1.645

=>This is good evidence to reject null hypothesis.

=> The actual rate is lower. (As H_{1} states)

Hope this helps!

:)

5 0
3 years ago
Algebra Linear Equations City Task (1)
Bogdan [553]

Answers:

1) Graph Line 1

a) Graph: Please, see the attached graph.

b) (Line 1) Main Street (Equation in slope intercept form): y=(1/3)x+4  

2) Graph Line 2

a) Graph: Please, see the attached graph.

b) Y intercept: (0,10)  

c) X intercept: (5,0)

d) (Line 2) Street Equation in Standard Form: y+2x=10

3) Grap Line 3

a) Graph: Please, see the attached graph.

b) (Line 3) Street Equation in Point Slope Form: <u>y-3=(5/3)(x+3)</u>

Street Equation in Slope Intercept Form: <u>y=(5/3)x+8</u>


Solution:

1) Graph Line 1: (Main Street)

a) Graph the line formed from the two given points (9,7) (-9,1)

Please, see the attached graph.

b) Find the street equation in slope intercept form

P1=(9,7)=(x1,y1)→x1=9, y1=7

P2=(-9,1)=(x2,y2)→x2=-9,y2=1

m=(y2-y1)/(x2-x1)

m=(1-7)/(-9-9)

m=(-6)/(-18)

m=6/18

m=(6/6)/(18/6)

m=1/3

Point Slope form:

y-y1=m(x-x1)

y-7=(1/3)(x-9)

Slope Intercept Form:

y-7=(1/3)x-(1/3)(9)

y-7=(1/3)x-(1)(9)/3

y-7=(1/3)x-9/3

y-7=(1/3)x-3

y-7+7=(1/3)x-3+7

y=(1/3)x+4


2) Graph Line 2

a) Graph the line given the x and y intercepts

y intercept: 10

x intercept: 5

Please, see the attached graph

b) Y intercept  

y intercept: b=10

Y intercept: (0,b)→Y intercept: (0,10)

c) X intercept

x intercept: a=5

X intercept: (a,0)→X intercept: (5,0)

d) Find the Street Equation in Standard Form

P1=(0,10)=(x1,y1)→x1=0, y1=10

P2=(5,0)=(x2,y2)→x2=5, y2=0

m=(y2-y1)/(x2-x1)

m=(0-10)/(5-0)

m=(-10)/(5)

m=-2

Point Slope Form:

y-y1=m(x-x1)

y-10=(-2)(x-0)

y-10=(-2)(x)

y-10=-2x

Standard Form:

y-10+10+2x=-2x+10+2x

y+2x=10


3)  Graph Line 3

a) Graph the line given a point and the slope. (-3,3); m=5/3

Point 1: P1=(-3,3)=(x1,y1)→x1=-3, y1=3

Slope: m=5/3

m=dy/dx

5/3=dy/dx→dy=5, dx=3

Point 2: P2=(x2,y2)

x2=x1+dx→x2=-3+3→x2=0

y2=y1+dy→y2=3+5→y2=8

Point 2: P2=(x2,y2)→P2=(0,8)

Please, see the attached graph.

b) Find the Street Equation in Point Slope Form

Point Slope Form:

y-y1=m(x-x1)

y-3=(5/3)(x-(-3))

y-3=(5/3)(x+3)

Slope Intercept Form:

y-3=(5/3)x+(5/3)(3)

y-3=(5/3)x+(5)(3)/3

y-3=(5/3)x+15/3

y-3=(5/3)x+5

y-3+3=(5/3)x+5+3

y=(5/3)x+8

3 0
3 years ago
All about easy points here
RoseWind [281]

Answer:

90

Step-by-step explanation:

The formula for right triangular prisms is simple; 1/2 × a × b × c. So simply plug in your numbers (doesn't matter the order you plug in).

1/2 × 12 × 5 × 3 = 90

5 0
3 years ago
Read 2 more answers
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