You can double the product of 9 and 4 to get to the product of 9 and 8
Compose the quadratic condition in standard shape, ax2 + bx + c = 0. Recognize the values of a, b, c. Write the Quadratic Equation. At that point substitute within the values of a, b, c. Simplify. Check the arrangements.
The answer is Function A. This is because Function A has a higher y-intercept than Function B. #brainliest
Answer:
center of circle: (0,6)
radius: 4
the point (sqrt17,7) is NOT located on this circle. It is outside of the circle. This circle cuts off at (sqrt15,7), therefor (sqrt17,7) is not included
