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Nat2105 [25]
3 years ago
15

Suppose we pick three people at random. For each of the 2.32 The following questions, ignore the special case where someone migh

t be born on February 29th, and assume that births are evenly distributed throughout the year.(a) What is the probability that the first two people share a birthday?(b) What is the probability that at least two people share a birthday?
Mathematics
1 answer:
inn [45]3 years ago
7 0

Answer:

(a) 1 in 365 or 0.2740%

(b) 0.8227%

Step-by-step explanation:

(a) For any given birthday date of the first person, there is a 1 in 365 chance that the second person shares the same birthday, therefore the probability that the first two people share a birthday is:

P = \frac{1}{365}=0.2740\%

(b) There are four possibilities that at least two people share a birthday, first and second, first and third, second and third, all three share a birthday. Therefore, the probability that at least two people share a birthday is:

P =3* \frac{1}{365}+ (\frac{1}{365})^2\\ P=0.8227\%

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