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almond37 [142]
2 years ago
5

A horizontal pole is attached to the side of a building. There is a pivot P at the wall and a chain is connected from the end of

the pole to a point higher up the wall. There is a tension force F in the chain. What is the moment of the force F about the pivot P?
Physics
1 answer:
PtichkaEL [24]2 years ago
6 0

Answer:

Fscos63

Explanation:

Given that a horizontal pole is attached to the side of a building. There is a pivot P at the wall and a chain is connected from the end of the pole to a point higher up the wall. There is a tension force F in the chain. What is the moment of the force F about the pivot P?

Taking the moment from the pivot point P, that means the moment at point p = 0

Then, if we consider the weight mg of the pole, according to the principle of equilibrium : sum of the upward forces equal to the sum of the downward forces.

Therefore, mg = Fsinø ....... (1)

Also, taking moment at point P

Let the length of the pole = s

The length of the weight of the pole = 1/2 S

Fscosø = mgs/2

The distance s will cancel out

2Fcosø = mg ...... (3)

Substitute mg in equation 1 into equation 3

2fcosø = fsinø

F will cancel out

Tanø = 2

Ø = tan^-1(2)

Ø = 63.4 degree

The moment of force F about pivot point P will be

Moment = force × distance

Moment = Fcos63 × S

Moment = Fscos63

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A 15 kg bucket of water is suspended by a very light ropewrapped around a solid uniform cylinder 0.300 m in diamter withmass 12.
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Answer:

Part a)

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Part b)

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Part c)

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Part d)

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Explanation:

Part a)

While bucket is falling downwards we have force equation of the bucket given as

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for uniform cylinder we will have

TR = I\alpha

so we have

T = \frac{1}{2}MR^2(\frac{a}{R^2})

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now we have

mg = (\frac{M}{2} + m)a

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T = \frac{12 \times 7}{2}

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Part b)

speed of the bucket can be found using kinematics

so we have

v_f^2 - v_i^2 = 2 a d

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Part c)

now in order to find the time of fall we can use another equation

v_f - v_i = at

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t = 1.7 s

Part d)

as we know that cylinder is at rest and not moving downwards

so here we can use force balance

F = T + Mg

F = 42 + (12 \times 9.81)

F = 159.7 N

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Explanation:

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