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marishachu [46]
3 years ago
8

What is the next step if the data from an investigation do not support the original hypothesis? A. The data are revised to suppo

rt the hypothesis. B. The data are incorrect and the experiment is run again. C. The data are adjusted to match the observations. D. The hypothesis is revised and another experiment is conducted.
Physics
2 answers:
gizmo_the_mogwai [7]3 years ago
6 0

Answer:  B. The data are incorrect and the experiment is run again.

A hypothesis is a supposition or explanation that is accepted in order to prove some natural phenomena by experimental procedures. If the data from the an investigation do not support the original hypothesis, the experiment should be performed again. With the subsequent trials the chances of getting accurate result increases.

Leno4ka [110]3 years ago
5 0
I believe the answer is D. <span>The hypothesis is revised and another experiment is conducted.</span>
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If one object is 103 km away and a second object is 106 km away, one could say that the second object is _____ times further awa
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1.03

Explanation:

\frac{object_{second}}{object_{first}} = \frac{106}{103} = 1.02912621359

Round to three significant digits

1.03

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3 years ago
A flat, circular, steel loop of radius 75 cm is at rest in a uniform magnetic field, as shown in an edge-on view in the figure (
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The solution to the questions are given as

  • t=40.39 \mathrm{sec}
  • \varepsilon &=(0.12v)e^{0.057t}
  • the direction of induced current will be Counterclock vise.

<h3>What is the direction of the current induced in the loop, as viewed from above the loop.?</h3>

Given, $B(t)=(1.4 T) e^{-0.057 t}$

$\varepsilon m f(\varepsilon)=-\frac{d \phi_{B}}{d t}

\quad$ and, $\phi_{B}=\int B \cdot d A=\int B \cdot d A \cdot \cos \theta$

\begin{aligned}\text { Here, } \theta &=30^{\circ} ; \\A &=\pi r^{2} \\a n \delta, R &=0.75 \mathrm{~m} \\\therefore \varepsilon &=-\frac{d}{d t}(B A \cdot \cos \theta)=-A \cdot \cos \theta \cdot \frac{d}{d t}(B(t)) \\\therefore \varepsilon &=-\pi R^{2} \cdot \cos \theta \cdot \frac{d}{d t}\left(e^{-0.057 t}\right)(1.4 T) \\\therefore \varepsilon &=+\pi(0.75)^{2} \cdot \cos 30 \cdot(0.057)(1.4) \cdot e^{-0.057 t}\left\{\because \frac{d}{d t} e^{-x}=-x \cdot e^{-x} .\right.\end{aligned}

\varepsilon &=(0.12v)e^{0.057t}

(b) Here, $\varepsilon_{0}=0.12 \mathrm{~V} \quad\left(a t_{2} t=0 \mathrm{sec}\right)$

\begin{aligned}&\therefore 1 . \varepsilon_{0}=\varepsilon_{0} \cdot e^{-e .057 t} \\&\therefore e^{0.057 t}=10 \quad \text { (taking log both thesides) } \\&\therefore 0.057 t=\ln (10)=2.303 \\&\therefore t=40.39 \mathrm{sec}\end{aligned}

c)

In conclusion, the direction of the induced current will be Counterclockwise.

Read more about current

brainly.com/question/13076734

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2 years ago
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Sitting = no movement
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