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Basile [38]
3 years ago
14

Draw the Lewis dot Structure for the molecule C2H6​

Physics
1 answer:
zzz [600]3 years ago
6 0

Answer:

This means that the Lewis dot structure for C2H6 must account for 14 valence electrons, either through bonding between atoms, or through lone pairs. So, the two C atoms are placed in the center of the molecule.

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If a = 8i + j - 2k and b = 5i - 3j + k show that a) a x b = -5i - 18j - 29k b) b X a = 50 + 18j +29k​
loris [4]

Recall the definition of the cross product with respect to the unit vectors:

i × i = j × j = k × k = 0

i × j = k

j × k = i

k × i = j

and that the product is anticommutative, so that for any two vectors u and v, we have u × v = - (v × u). (This essentially takes care of part (b).)

Now, given a = 8i + j - 2k and b = 5i - 3j + k, we have

a × b = (8i + j - 2k) × (5i - 3j + k)

a × b = 40 (i × i) + 5 (j × i) - 10 (k × i)

… … … … - 24 (i × j) - 3 (j × j) + 6 (k × j)

… … … … + 8 (i × k) + (j × k) - 2 (k × k)

a × b = - 5 (i × j) - 10 (k × i) - 24 (i × j) - 6 (j × k) - 8 (k × i) + (j × k)

a × b = - 5k - 10j - 24k - 6i - 8j + i

a × b = -5i - 18j - 29k

7 0
2 years ago
Take another look at lines 2 and 3. Suppose you use distance and time between any pair of neighboring dots to calculate speed:
Nataly [62]

Answer:

Add the two speeds together.

Then, divide the sum by two. This will give you the average speed for the entire trip. So, if Ben traveled 40 mph for 2 hours, then 60 mph for another 2 hours, his average speed is 50 mph.

8 0
3 years ago
Read 2 more answers
A stone is dropped from a tower 100 meters above the ground. The stone falls past ground level and into a well. It hits the wate
Elan Coil [88]
Make the base of the building zero. Then the initial distance is 100m, final distance unknown x. Use gravity, time and initial velocity to solve for final distance.
x - 100 = (0)(5) +(1/2)(-9.81)(5^2)
x - 100 = 0 - 122.625
x = -122.625 + 100
x = -22.625 m below ground
7 0
3 years ago
List the three types of symbiotic relationships. For each type of symbiotic relationship, explain how the two organisms are affe
Virty [35]
<span>The three major types of symbiosis are mutualism, where both species benefit, commensalism, where one species benefits and the other is unaffected, and parasitism, where one species benefits and the other is harmed. Symbiotic relationships can occur within an organism's body or outside of it.                                                                                                                                                                              </span><span>Examples of mutualism include the relationship between single-celled organisms or animals that incorporate algae into their bodies. They give the algae necessary nutrients, and in return receive chemical energy from the photosynthetic algae. Animals that have this sort of relationship include some sponges, sea anemones and clams. Examples of commensalism include remora fish attaching to the bodies of sharks and eating scraps of food that escape their jaws, and barnacles living on the jaws of whales with a similar feeding strategy. Plants have commensal relationships as well, such as many orchids that grow on taller plants and benefit from the additional sunlight they obtain, without actually stealing nutrients from the host plant. Parasitic relationships are many, and parasites include all disease-causing organisms. This category also includes insects such as fleas that suck the blood of hosts externally. Parasitism is a very efficient strategy for organisms, and parasites often lose many of the features of non-parasitic life forms, instead relying on their hosts for many of the functions of life.</span>
5 0
2 years ago
A very long train is rolling at 4 m/s along a straight track. An observer is standing on the ground very dangerously close to th
hichkok12 [17]

Answer:

A. \vec{r}=(6\frac{m}{s})t\ \ \hat{i}

B.  t = 50 s

Explanation:

A. The vectorial equation of the person who is getting closer to the other person is:

\vec{r}=\vec{v}t

r: position vector

v: speed vector = 6m/s i  (if you consider the motion as a horizontal motion)

Then, you replace and obtain:

\vec{r}=(6\frac{m}{s})t\ \ \hat{i}

B. The time is:

t=\frac{d}{v}

d: distance to the observer = 300m

v: speed of the person on the car = 6.00 m/s

t=\frac{300m}{6m/s}=50s

4 0
3 years ago
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