Answer:
No, there is no evidence that the manufacturer has a problem with underfilled or overfilled bottles, due that according our results we cannot reject the null hypothesis.
Explanation:
according to this exercise we have the following:
σ^2 =< 0.01 (null hypothesis)
σ^2 > 0.01 (alternative hypothesis)
To solve we can use the chi-square statistical test. To reject or not the hypothesis, we have that the rejection region X^2 > 30.14
Thus:
X^2 = ((n-1) * s^2)/σ^2 = ((20-1)*0.0153)/0.01 = 29.1
Since 29.1 < 30.14, we cannot reject the null hypothesis.
Answer:
c. 0.200 M HCI(aq)
Explanation:
The titration of a base as NH3 with hydrochloric acid is:
NH3 + HCl → NH4Cl
<em>Where 1 mole of NH3 reacts per mole of HCl</em>
<em />
The recommended volume to read in a burette is between 60 and 80% of its capacity.
That is 60% 50.0mL = 30mL and 80% 50.0mL = 40mL must be spent.
A 6.00M HCl spend:
20mL * (0.3mol/L) * (1L/ 6.00M) = 1mL. This solution is not the ideal for the titration.
A 0.3M HCl spend:
20mL * (0.3mol/L) * (1L/ 0.3M) = 20mL. This solution is not the ideal for the titration.
A 0.200M HCl spend:
20mL * (0.3mol/L) * (1L/ 0.200M) = 30mL. This solution ideal for the titration.
A 0.100M HCl spend:
20mL * (0.3mol/L) * (1L/ 0.100M) = 60mL. This solution is not the ideal for the titration.
Right option is:
<h3>c. 0.200 M HCI(aq)</h3>
Answer:
In Tcl the words in a command are always exposed to two layers of interpretation: First, Tcl interprets them and prepares them as arguments to a routine. Second, the routine interprets those arguments according to its own principles. double substitution occurs when Tcl performs substitutions on original command and a routine then performs substitutions on the resulting arguments. Care is required in these cases to avoid errors, including vulnerability to injection attacks.
Explanation:
this probably wont help but here
Answer:
option b is correct
Explanation:
Metals are particularly good conductors of heat because their particles are very closely packed so the vibrations are passed on very quickly. They also contain large numbers of free electrons. These drift slowly through the structure, giving metals their strength and other properties. As the metal is heated, the free electrons closest to the heat source are heated. This makes them move faster and they travel through the metal, colliding with both atoms and other electrons. This naturally makes these vibrate faster (or move through the metal faster in the case of collisions with other free electrons). Thus, the heat is passed quickly through the metal.
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The answer is c this is the answer