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zepelin [54]
3 years ago
12

What is another name for dihydrogen monoxide?

Chemistry
1 answer:
Lilit [14]3 years ago
4 0

Answer:

WATER

Explanation:

The another name for dihydrogen monoxide is water

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Please help with 3! Please give only the correct answer...
cupoosta [38]
The answer is:  " 1.75 * 10 ^(-10)  m " .
_________________________________________________________
Explanation: 
_________________________________________________________
This very question asked for "Question Number 3 (THREE) ONLY, which is fine!
_________________________________________________________
Given: " 0.000000000175 m " ;  write this in "scientific notation.
_________________________________________________________
Note:   After the "first zero and the decimal point" {Note: that first zero that PRECEDES the decimal point in merely a "placeholder" and does not count as a "digit" — for our purposes} —
                     There are NINE (9) zeros, followed by "175"
_______________________________________________________
To write in "scientific notation", we find the integer that is written, as well, as any "trailing zeros" (if there are any—and by "trailing zeros", this means any number consecutive zeros/and starting with "the consecutive zeros" only —whether forward (i.e., "zeros following"; or backward (i.e. "zeros preceding").

In our case we have "zeros preceding";  that is a decimal point with zeros PRECEDING an "integer expression"<span>
</span><span> (the "integer" is "175").</span>
______________________________________________________
We then take the "integer expression" (whatever it may be:  12, 5, 30000001 ; or could be a negative value,  etc.) ;  

→  In our case, the "integer expression" is:  "175" ;

and take the first digit (if the expression is negative, we take the negative value of that digit;  if there is only ONE digit (positive or negative), then that is the digit we take ;

And write a decimal point after that first digit (unless in some cases, there is only one digit);  and follow with the rest of the consecutive digits of that 'integer expression' ;

→ In our case:  "175" ; becomes:  " 1.75" .
__________________________________________________
Then we write:  "  * 10^ "
__________________________________________________
   {that is "[times]"; or "multiplied by" :    [10 raised exponentially to the power of  <u>     </u> ]._____________________________________________________
 And to find that power, we take the "rewritten integer value (i.e. "whole number value that as been rewritten to a single digit with a decimal point"); and count the [number of "trailing zeros";  if there are any; PLUS the number of decimal places one goes] ; and that number is the value to which "10" is raised.
{If there are none, we write:  " * 10⁰ " ;    since "any value, raised to the "zero power", equals "1" ; so " * 10⁰ " ; is like writing:  " * 1 " .

If there are "trailing zeros" AND/OR or  any number of decimal places,  to the "right" of this expression; the combined number of spaces to the right is: 
  { the numeric value (i.e. positive number) of the power to which "10" is raised }.

Likewise, if there are "trailing zeros" AND/OR or any number of decimal places, to the "LEFT" of this expression; the combined number of spaces to the LEFT is the value of the power which "10" is raised to; is that number—which is a negative value.

In our case:  we have:  0.000000000175 * 10^(-10) .

Note:  The original notation was:

             →  " 0.000000000175 m "

{that is:  "175" [with 9 (nine) zeros to the left].}.

We rewrite the "175" ("integer expression") as:

"1.75" .
____________________________________________________
So we have:
         →   " 0.000000000175 m " ;

Think of this value as:

        " 0. 0000000001{pseudo-decimal point}75   m ".

And count the number of decimal spaces "backward" from the
      "pseudo-decimal point" to the actual decimal; and you will see that there are "10" spaces (to the left).   
______________________________________________________
Also note:  We started with "9 (nine)" preceding "zeros" before the "1" ;  now we are considering the "1" as an "additional digit" ;
             →  "9 + 1 = 10" .
______________________________________________________
Since the decimals (and zeros) come BEFORE (precede) the "175" ; that is, to the "left" of the "175" ; the exponent to which the "10" is raised is:
 "NEGATIVE TEN" { "-10" } .

So we write this value as:  " 1.75 * 10^(-10)  m " .  

{NOTE:  Do not forget the units of measurement; which are "meters" —which can be abbreviateds as:  "m" .} . 
______________________________________________________
The answer is:  " 1.75 * 10^(-10)   m " .
______________________________________________________
4 0
3 years ago
PLEASE HELP!!! I'll give brainliest answer
ELEN [110]

Answer:

1. MG

2. N

3. F

4. NA

5. O

6. K

3 0
2 years ago
Read 2 more answers
What Household item turns electrical energy into radiant energy
luda_lava [24]

Answer:

Lamps and televisions

Explanation:

I think those qualify.

6 0
2 years ago
Read 2 more answers
Place the following transitions of the hydrogen atom in order from longest to shortest wavelength of the photon emitted. Rank fr
gizmo_the_mogwai [7]

Answer:

7 to 4     (higher  \lambda)

5 to 3

3 to 2

4 to 2   (lower  \lambda)

Explanation:

We can use the Rydberg formula which relates the wavelength of the photon emissions to the principle quantum numbers involved in the transition:

\frac{1}{\lambda}=R((\frac{1}{n_1^2})-(\frac{1}{n_2^2}))

with n_1 final n, and n_2 initial n

evaluating for each transition:

7 to 4 \frac{1}{\lambda} = R((\frac{1}{4^2})-(\frac{1}{7^2}))= R(1/16-1/49)=R(0.042)

5 to 3 \frac{1}{\lambda}= R(1/9-1/25)=R(0.071)

4 to 2 \frac{1}{\lambda}= R(1/4-1/16)=R(0.1875)

3 to 2 \frac{1}{\lambda}= R(1/4-1/9)=R(0.139)

Note that the above formula is written for \frac{1}{\lambda}, so lower \frac{1}{\lambda} value obtained involves higher \lambda.

So we should order from lower to higher \frac{1}{\lambda}

7 to 4     (higher  \lambda)

5 to 3

3 to 2

4 to 2   (lower  \lambda)

Note: Take into account that longer wavelength involves lower energy (E=\frac{hc}{\lambda}).

3 0
3 years ago
A 20.0 g sample of copper at 25.0 °c absorbs 475 j. What is the final temperature of the copper? (specific heat capacity of copp
maks197457 [2]

Given data:

Mass of copper (m)  = 20.0 g

Initial temperature of Copper (T1)=  25 C

Final temperature = T2

Heat absorbed by copper (Q) = 475 J

Specific heat of Copper (c) = 0.385 J/g C

Formula:

Q = mcΔT

   = mc(T2-T1)

475 = 20*0.385*(T2-25)

62.08 = T2-25

T2 = 87.08 = 87.1 C


8 0
3 years ago
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