<h2>
Answer:HCl</h2>
Explanation:
For 
For 
The reaction between 
and 
is
→
So,one mole of requires one mole of
moles of requires moles of
But there are only 
moles of available.
will be consumed first.
So, is the limiting reagent.
Use the coefficients as a ratio. 1:6 = x:24. You can write these as fractions and cross multiply, 6x=24. Solve and x=4, so four molecules would be needed
Solve first for the number of moles of sodium given that the mass is 2500 g by dividing the given mass by the molar mass of sodium.
moles sodium = 2500 g / 23 g/mol
moles sodium = 108.7 moles
Since in every mole of NaCl, there is only one mole of sodium then, we conclude that there are also 108.7 moles of NaCl. Multiplying the number of moles to the molar mass of sodium chloride (58.44), the answer would be 6,352.17 grams.
