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spayn [35]
3 years ago
12

A small amount of a solid is added to water. The observation made after fifteen minutes is shown in the figure. Which of these s

olids has been probably added to water? A) oil B) sand C) sugar D) wood chips

Chemistry
1 answer:
natulia [17]3 years ago
4 0

Answer:

B) sand

Explanation:

A) Oil is a wrong choice because it is a liquid not a solid and also if it is oil, it will float over the water surface as a droplets.

B) Sand is the right choice, because sand is a solid and it does not dissolve in water and stabilizes at the bottom.

C) Sugar is a wrong choice, because small amount of sugar will dissolve in water and be a homogeneous solution and does not appear as a particles.

D) Wood ships is also a wrong choice, even it is a solid and does not dissolve in water, but it will float over the water surface.

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Is CO2 a covalent or ionic bond? will give brainliest for the correct answer​
NeX [460]

Answer:

covalent bond

Explanation:

a covalent bond happens between two nonmetals

a ionic bond happens between a metal and a non metal

CO2 is a bond between carbon and oxygen

carbon and oxygen are both non metals therefore CO2 is a covalent bond

4 0
2 years ago
Read 2 more answers
Maria wants to determine which type of disinfectant kills the most bacteria.
murzikaleks [220]

Answer:

well she can test both of the soap by putting one on and plate and another on the other plate and which ever is cleaner is your answer

6 0
3 years ago
Read 2 more answers
0.415 g of an unknown triprotic acid are used to make a 100.00 mL solution. Then 25.00 mL of this solution is transferred to an
Arturiano [62]

Answer:

Explanation:

Initial burette reading = 1.81 mL

final burette reading = 39.7 mL

volume of NaOH used = 39.7 - 1.81 = 37.89 mL .  

37.89 mL of .1029 M NaOH is used to neutralise triprotic acid

No of moles contained by 37.89 mL of .1029 M NaOH

= .03789 x .1029 moles

= 3.89 x 10⁻³ moles

Since acid is triprotic ,  its equivalent weight = molecular weight / 3

No of moles of triprotic acid = 3.89 x 10⁻³ / 3

= 1.30   x 10⁻³ moles .

8 0
3 years ago
When maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas write the balanved equati
babunello [35]

Answer: When maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas then balanced equation is MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}.

Explanation:

The word equation is given as maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas.

Now, in terms of chemical formulae this reaction equation will be as follows.

MnO_{2} + HCl \rightarrow H_{2}O + MnCl_{2} + Cl_{2}

Here, number of atoms on reactant side are as follows.

  • Mn = 1
  • O = 2
  • H = 1
  • Cl = 1

Number of atoms on product side are as follows.

  • Mn = 1
  • O = 1
  • H = 2
  • Cl = 4

To balance this equation, multiply HCl by 4 on reactant side and multiply H_{2}O by 2 on product side. Therefore, the equation can be rewritten as follows.

MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}

Hence, number of atoms on reactant side are as follows.

  • Mn = 1
  • O = 2
  • H = 4
  • Cl = 4

Number of atoms on product side are as follows.

  • Mn = 1
  • O = 2
  • H = 4
  • Cl = 4

Since, this equation contains same number of atoms on both reactant and product side. Therefore, this equation is now balanced equation.

Thus, we can conclude that when maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas then balanced equation is MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}.

6 0
3 years ago
Complete the table below by deciding whether a precipitate forms when aqueous solutions A and B are mixed. If a precipitate will
stiks02 [169]

The reaction between copper II chloride and sodium sulfide as well as lead II nitrate and potassium sulfate both produce precipitates.

The solubility of a substance in water is in accordance with the solubility rules.  It is possible that a solid product may be formed when two aqueous solutions are mixed together. That solid product is referred to as a precipitate.

Now, we will consider each reaction individually to decode whether or not a precipitate is possible.

  • In the first reaction, we have; CuCl2(aq) + Na2S(aq) ---->CuS(s) + 2NaCl(aq). A precipitate (CuS) is formed.
  • In the second reaction, Pb(NO3)2(aq) + 2KNO3(aq) ----> PbSO4(s) + KNO3(aq), a precipitate PbSO4 is formed
  • In the third reaction, NH4Br(aq) + NaOH(aq) ----->NH3(g)  + NaBr(aq) + H2O(l), a precipitate is not formed here.

Learn more: brainly.com/question/11969651

6 0
2 years ago
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