Find coordinate of points
Point P coordinates are (x,y) =
x is same that point L, y = 0 .
Then coordinates for P = (a,0)
Point M coordinates
x is same that point N, x=b
y is same that point L , y=c
Then coordinates for M = (b,c)
When hav epoins (x1,y1) and (x2,y2)
slope is (y2-y1)/(x2-x1)
(-3,4) and (5,-1)
slope=(-1-4)/(5-(-3))=-5/(5+3)=-5/8
slope=-5/8
Let point (x, y) be any point on the graph, than the distance between (x, y) and the focus (3, 6) is sqrt((x - 3)^2 + (y - 6)^2) and the distance between (x, y) and the directrix, y = 4 is |y - 4|
Thus sqrt((x - 3)^2 + (y - 6)^2) = |y - 4|
(x - 3)^2 + (y - 6)^2 = (y - 4)^2
x^2 - 6x + 9 + y^2 - 12y + 36 = y^2 - 8y + 16
x^2 - 6x + 29 = -8y + 12y = 4y
(x - 3)^2 + 20 = 4y
y = 1/4(x - 3)^2 + 5
Required answer is f(x) = one fourth (x - 3)^2 + 5
Answer:
250 litters
Step-by-step explanation:
To solve this question, we first need to know the conversion from cubic meter to liter.
1 cubic meter is equal to 1000 liters.
So, if we have 1/4 cubic meter, we can use a rule of three to find how many liters we will need:
1 m3 -> 1000 L
1/4 m3 -> x L
x * 1 = (1/4) * 1000
x = 1000 / 4 = 250 L
So we need 250 liters of water.
My best guess is that 73 cartons are needed. Here's how:
876/12 ( because the jugs are shipped in cartons containing 12) = 73
This is just a guess, I'm sorry if someone proves me wrong, but this is what I have.
