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3 years ago

Which function is described by values in the table?

Mathematics

1 answer:

Sveta_85 [38]3 years ago

7 0

One way to approach this problem is to go ahead and find the actual equation in slope-intercept form.

The slope of the line thru (3,6) and (5,4) is m = (6-4) / (3-5), or -2/2, or -1.

Subbing the known values of m, x and y, we get:

4 = -(5) + b. Then b = 9.

The correct equation (representing the data values in the table) is y = -x + 9.

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Solve the area formula for h

White raven [17]

The answer is C: $h = \frac{2A}{b}$

Starting with the given formula for the area, A = 1/2hb, the first step is to isolate h by using the multiplicative inverse of b, which is $\frac{1}{b}$ on both sides of the equation:

$A(\frac{1}{b}) = \frac{1}{2}hb* (\frac{1}{b})$

The result will be:

$\frac{A}{b} = \frac{1}{2}h$

The last step is to use the multiplicative inverse of $\frac{1}{2}$ , which is 2 or $\frac{2}{1}$ to further isolate the variable <em>h </em>:

$\frac{A}{b} (\frac{2}{1}) = (\frac{2}{1}) \frac{1}{2} h$

The formula for h will be:

$h = \frac{2A}{b}$ which is the option C in your question.

4 0

3 years ago

Given $a \equiv 1 \pmod{7}$, $b \equiv 2 \pmod{7}$, and $c \equiv 6 \pmod{7}$, what is the remainder when $a^{81} b^{91} c^{27}$

Blizzard [7]

$\begin{cases}a\equiv1\pmod7\\b\equiv2\pmod7\\c\equiv6\pmod7\end{cases}$

$a^{81}\equiv1^{81}\equiv1\pmod7$

$b^{91}\equiv2^{91}\pmod7$

$2^{91}\equiv(2^3)^{30}\times2^1\equiv8^{30}\times2\pmod7$
$8\equiv1\pmod7$
$2\equiv2\pmod7$
$\implies2^{91}\equiv1^{30}\times2\equiv2\pmod7$

$c^{27}\equiv6^{27}\pmod7$

$6^{27}\equiv(-1)^{27}\equiv-1\equiv6\pmod7$

$\implies a^{81}b^{91}c^{27}\equiv1\times2\times6\equiv12\equiv5\pmod7$

6 0

3 years ago

Express the following rate as a unit rate.

Allisa [31]

Answer:

21 jacks/min

or 21 jacks per minute

Step-by-step explanation:

63/3 = 21

write it as ___ unit/rate

please mark brainliest

6 0

2 years ago

Nesterboy [21]

Answer:

Step-by-step explanation:

Answer

2/3

Explanation

For f(x) = g(x) we should equate the two functions to get the value of x.

f(x) = g(x)

−3x + 4 = 2

-3x + 4 - 4 = 2 - 4

-3x = -2

Dividing by -3 on both sides;

(-3x)/-3 = (-2)/-3

x = 2/3

7 0

3 years ago

BRAINLIESTT ASAP! PLEASE HELP ME :)

Lubov Fominskaja [6]

Answer: $\sqrt{37}$

=====================================

Work Shown:

6x-y = -3 is the same as 6x-y+3 = 0

6x-y+3 = 0 is the form Ax+By+C = 0 with A = 6, B = -1, C = 3.

The distance d that line is from the point (p,q) = (6, 2) is found by the following

$d = \frac{A*p+B*q+C}{\sqrt{A^2+B^2}}\\\\d = \frac{6*6-1*2+3}{\sqrt{6^2+(-1)^2}}\\\\d = \frac{36-2+3}{\sqrt{36+1}}\\\\d = \frac{37}{\sqrt{37}}\\\\d = \frac{37\sqrt{37}}{37}\\\\d = \sqrt{37}\\\\d \approx 6.08276\\\\$

7 0

3 years ago