Find the surface area of a square pyramid with side length 5 ft and slant height 7 ft.
2 answers:
Answer:5x5=25 fts
4(1/2 x 5ft x7 ft) = 70 fts
Add them up and you get
Answer= 95fts
Step-by-step explanation:
Answer:
99.33ft^2
Step-by-step explanation:
The surface area of a square pyramid is expressed as;
TSA = a²+2a√a²/4 + h²
Given that
a = 5ft
h = 7ft
Substitute
TSA = 5²+2(5)√5²/4 + 7²
TSA = 25+10√25/4 + 49
TSA = 25 + 10√(221/4)
TSA = 25 + 10(√55.25)
TSA = 25 + 10(7.433)
TSA = 25 + 74.33
TSA = 99.33ft^2
Hence the surface area of a square pyramid with side length 5 ft and slant height 7 ft is 99.33ft^2
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Yea but it would be an obtuse triangle
79+23=102
180-102=78
the third angle is 78 degrees
Solution:
C=32.50t+8.50
236=32.50t+8.50
236-8.50=32.50t
227.50=32.50t
227.50/32.50=32.50t/32.50
t=7
The family bought 7 tickets.
No, because BC and BD are not the same lengths. If AB = BC, then AB and BD are not the same lengths -> ABDE is not a rhombus.
Answer:
8
Step-by-step explanation:
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