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Svetradugi [14.3K]
3 years ago
15

Find the surface area of a square pyramid with side length 5 ft and slant height 7 ft.

Mathematics
2 answers:
Anna007 [38]3 years ago
6 0

Answer:5x5=25 fts

4(1/2 x 5ft x7 ft) = 70 fts

Add them up and you get

Answer= 95fts

Step-by-step explanation:

harina [27]3 years ago
3 0

Answer:

99.33ft^2

Step-by-step explanation:

The surface area of a square pyramid is expressed as;

TSA = a²+2a√a²/4 + h²

Given that

a = 5ft

h = 7ft

Substitute

TSA = 5²+2(5)√5²/4 + 7²

TSA = 25+10√25/4 + 49

TSA = 25 + 10√(221/4)

TSA = 25 + 10(√55.25)

TSA = 25 + 10(7.433)

TSA = 25 +  74.33

TSA = 99.33ft^2

Hence the surface area of a square pyramid with side length 5 ft and slant height 7 ft is 99.33ft^2

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Ann is adding water to a swimming pool at a constant rate. The table below shows the amount of water in the pool after different
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Answer:

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(b)  65 gallons

Step-by-step explanation:

From inspection of the table, we can see that <u>as time increases, the amount of water in the pool increases</u>.

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The rate at which the water is increasing is the <em>rate of change</em> (which is also the <em>slope </em>of a linear function).

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Input these into the slope formula:

\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{197-153}{12-8}=\dfrac{44}{4}=11

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