I think the answer for your question is B
Factor the following:
x^2 - 16 x + 63
The factors of 63 that sum to -16 are -7 and -9. So, x^2 - 16 x + 63 = (x - 7) (x - 9):
Answer: (x - 7) (x - 9)
The probability that the mean clock life would differ from the population mean by greater than 12.5 years is 98.30%.
Given mean of 14 years, variance of 25 and sample size is 50.
We have to calculate the probability that the mean clock life would differ from the population mean by greater than 1.5 years.
μ=14,
σ=
=5
n=50
s orσ =5/
=0.7071.
This is 1 subtracted by the p value of z when X=12.5.
So,
z=X-μ/σ
=12.5-14/0.7071
=-2.12
P value=0.0170
1-0.0170=0.9830
=98.30%
Hence the probability that the mean clock life would differ from the population mean by greater than 1.5 years is 98.30%.
Learn more about probability at brainly.com/question/24756209
#SPJ4
There is a mistake in question and correct question is as under:
What is the probability that the mean clock life would differ from the population mean by greater than 12.5 years?
Idk if she's too young to learn cross multiply, but this is an easier method.
Multiply everything by 4 which cancels out the 4 on the left side.
36z-16/5 <= 7z + 2
Now multiply everything by 5, cancelling out the right side 5.
36z-16 <= 35z + 10
Solve the equation normally
z-16<=10
z<=36
Answer:
4 is the length of a side.
Step-by-step explanation:
16 divided by 4 equals 4