What are the objects listed?
Caesium is more reactive than sodium because when it is burned sodium will smell, taste, and look like poop
The equilibrium constant for the reaction is:
K subscript eq equals StartFraction StartBracket upper H subscript 2 EndBracket superscript 2 StartBracket upper O subscript 2 EndBracket over StartBracket upper H subscript 2 upper O EndBracket superscript 2 EndFraction.
<h3>What is equilibrium constant? </h3>
The equilibrium constant (Kₑq) for a given reaction is simply defined as the ratio of the concentration of the products raised to their coefficient to the concentration of the reactants raised to their coefficient.
For example, the equilibrium constant Kₑq for the reaction below is given as
2A <=> B
Kₑq = [B]/[A]²
<h3>How to determine the equilibrium constant </h3>
- 2H₂O(g) <=> 2H₂(g) + O₂(g)
- Equilibrium constant (Kₑq) =?
Kₑq = [H₂]²[O₂] / [H₂O]²
K subscript eq equals StartFraction StartBracket upper H subscript 2 EndBracket superscript 2 StartBracket upper O subscript 2 EndBracket over StartBracket upper H subscript 2 upper O EndBracket superscript 2 EndFraction.
Learn more about equilibrium constant:
brainly.com/question/17960050
Answer:
Mg^2+ and OH- are the chemical species present at the equilibrium. Mg(OH)2 will not affect the equilibrium.
Explanation:
Step 1: data given
Reactants are Solid Mg(OH)2 and H2O(l)
Kc1 = 1.8 * 10^-11
Step 2: The balanced equation
Mg(OH)2(s) ⇄ Mg2+(aq) + 2OH-(aq)
Step 3: Define the equilibrium constant Kc
Kc = [OH-]²[Mg^2+]
Pure solids and liquids do not have any effect or influence on the equilibrium in the reaction. So they are not included in the equilibrium constant expression.
This means Mg^2+ and OH- are the chemical species present at the equilibrium. Mg(OH)2 will not affect the equilibrium.
