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sergey [27]
3 years ago
10

He deposits $4,500 in an account that pays 1.5% interest, compounded quarterly. What is his balance after 5 years?\

Mathematics
1 answer:
anygoal [31]3 years ago
6 0

Answer:

His balance is $4,849.65 after 5 years

Step-by-step explanation:

A = P(1 + r/n)^nt

A = future value = ?

P = present value = $4,500

r = interest rate = 1.5% = 0.015

n = number of periods = 4

t = time = 5 years

A = P(1 + r/n)^nt

= 4,500(1 + 0.015/4)^4*5

= 4,500(1 + 0.00375)^20

= 4,500(1.00375)^20

= 4,500(1.0777)

= 4,849.65

A = $4,849.65

His balance is $4,849.65 after 5 years

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where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤
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THIS IS THE COMPLETE QUESTION BELOW

The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.

Answer

$168.27

Step by step Explanation

Given p=90000/400+3x

With the limits of 40 to 50

Then we need the integral in the form below to find the average price

1/(g-d)∫ⁿₐf(x)dx

Where n= 40 and a= 50, then if we substitute p and the limits then we integrate

1/(50-40)∫⁵⁰₄₀(90000/400+3x)

1/10∫⁵⁰₄₀(90000/400+3x)

If we perform some factorization we have

90000/(10)(3)∫3dx/(400+3x)

3000[ln400+3x]₄₀⁵⁰

Then let substitute the upper and lower limits we have

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3000[0.056]

=168.27

the average price p on the interval 40 ≤ x ≤ 50 is

=$168.27

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