What is the sum of the arithmetic sequence 8,15,22..., if there are 26 terms?
1 answer:
Answer:
2,483
Step-by-step explanation:
8+15+22+29+36+43+50+57+64+71+78+85+92+99+106+113+120+127+134+141+148+155+162+169+176+183=2483
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Too much work!!!!!!!!!!!!
La formula para sacar la pendiente:
Y2-Y1/X2-X1
Respuesta:
Y2-Y1/X2-X1= -2-(-10)/-1-(-1)
= -2+10/ -1+1= 8
R=8
Espero que te sirva
36 different outcomes.
6 x 6 = 36
Each side of dice 1 could have a counter match of 6 possibilities x 6
133 x 99 = 13167
100% correct
Answer:
the answer is 2. there arwnt any number lines so
