What is the sum of the arithmetic sequence 8,15,22..., if there are 26 terms?
1 answer:
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Answer:
Step-by-step explanation:
The given equation is:
so, we first isolate the exponential form that contains the unknown "z" in the exponent, by dividing both sides by 0.5:
Now we bring the exponent down by applying the natural log function on both sides, and then solve for "z":
Splitting up the interval [0, 6] into 6 subintervals means we have
![[0,1]\cup[1,2]\cup[2,3]\cup\cdots\cup[5,6]](https://tex.z-dn.net/?f=%5B0%2C1%5D%5Ccup%5B1%2C2%5D%5Ccup%5B2%2C3%5D%5Ccup%5Ccdots%5Ccup%5B5%2C6%5D)
and the respective midpoints are
. We can write these sequentially as 
where 
.
So the integral is approximately
Recall that
so our sum becomes
and the respective midpoints are
So the integral is approximately
Recall that
so our sum becomes
C)
you look at were the graph starts to decrease then look at the X-VALUE not the y-value
the x-val at the start of the decrease is -3 and at the end of it it is 2 therefor -3
x 2
you look at were the graph starts to decrease then look at the X-VALUE not the y-value
the x-val at the start of the decrease is -3 and at the end of it it is 2 therefor -3