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3 years ago

CH4 + 2 02 - CO2 + 2 H2O

Chemistry

1 answer:

sladkih [1.3K]3 years ago

7 0

answer: 6.875 moles

nCH4 = nCO2 = 110/(12 + 4) = 6.875

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Summarize the characteristics of each type of element below

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3 years ago

How many liters of nitrogen gas is produced if 50.0L of water is produced at STP?

Alona [7]

Answer:

25.0 liter of nitrogen gas

Explanation:

1. Chemical equation

Ammonium nitrite is a solid compound that decomposes into nitrogen gas and water vapor as per this chemical equation:

$NH_4NO_2(s)\rightarrow N_2(g)+2H_2O(g)$

2. Mole ratio

$1molN_2(g)/2molH_2O(g)$

3. Volume ratio

Since, both species are gases and are at same temperature and pressure, the volume ratio is equal to the mol ratio.

Thus, the volume ratio is:

$1literN_2(g)/2literH_2O(g)$

4. Use the volume ratio with the known amount of water produced

$50.0literH_2O(g)\times 1literN_2(g)/2literH_2O(g)=25.0literN_2(g)$

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3 years ago

Why does iron not fit the pattern in column 7

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4 years ago

When the equation Sn + HNO₃ → SnO₂ + NO₂ + H₂O is balanced in acidic solution, what is the smallest whole-number coefficient for

balu736 [363]

Answer:

Explanation:

Hello,

In this case, for the given reaction we first assign the oxidation state for each species:

$Sn^0 + H^+N^{5+}O^{-2}_3 \rightarrow Sn^{4+}O_2 + N^{4+}O^{2-}_2 + H^+_2O^-$

Whereas the half reactions are:

$Sn^0+2H_2O \rightarrow Sn^{4+}O_2 +4H^++4e^-\\\\H^++H^+N^{5+}O^{-2}_3 +1e^-\rightarrow N^{4+}O^{2-}_2+H_2O$

Next, we exchange the transferred electrons:

$1\times(Sn^0+2H_2O \rightarrow Sn^{4+}O_2 +4H^++4e^-)\\\\4\times (H^++H^+N^{5+}O^{-2}_3 +1e^-\rightarrow N^{4+}O^{2-}_2+H_2O)\\\\\\Sn^0+2H_2O \rightarrow Sn^{4+}O_2 +4H^++4e^-\\\\4H^++4H^+N^{5+}O^{-2}_3 +4e^-\rightarrow 4N^{4+}O^{2-}_2+4H_2O$

Afterwards, we add them to obtain:

$Sn^0+2H_2O+4H^++4H^+N^{5+}O^{-2}_3 \rightarrow Sn^{4+}O_2 +4H^++4N^{4+}O^{2-}_2+4H_2O$

By adding and subtracting common terms we obtain:

$Sn^0+4H^+N^{5+}O^{-2}_3 \rightarrow Sn^{4+}O_2 +4N^{4+}O^{2-}_2+2H_2O$

Finally, by removing the oxidation states we have:

$Sn + 4HNO_3 \rightarrow SnO_2 + 4NO_2 + 2H_2O$

Therefore, the smallest whole-number coefficient for Sn is 1.

Regards.

6 0

3 years ago