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Leona [35]
4 years ago
8

A sample of Strontium-90 is found to have decayed to one-fourth of its original amount after 58.2 years. What is the half-life o

f strontium-90?
Chemistry
2 answers:
mafiozo [28]4 years ago
3 0
The half-life of strontium-90 is 28.8 years.
Igoryamba4 years ago
3 0

Answer: Half life of Sr-90 is 29.1 years.

Explanation: Half life is the time in which the substance remains halve of its original amount. Let's say originally we have 100 grams of Sr-90. From given information, it remains one-fourth of its original amount in 58.2 years.

One-fourth of 100 gram will be 25 gram. The equation used for solving this type of problems is:

\frac{N}{N_0}=(0.5)^n

where, n is the number of half lives, N_0 is the original amount of the radioactive substance and N is the remaining amount.

From above information:

N_0 = 100

N = 25

Let's plug in these values in the equation and find out the value of n.

\frac{25}{100}=(0.5)^n

\frac{1}{4}=(0.5)^n

0.25=(0.5)^n

(0.5)^2=(0.5)^n

n = 2

From above calculations, the value of n is 2 means there are two half lives.

From the given time and the value of n, we can calculate the half life of the substance using the equation:

half life = \frac{T}{n}

(Where T stands for time)

Let's plug in the values in the equation:

half life = \frac{58.2years}{2}

half life = 29.1 years

So, half life of Sr-90 is 29.1 years.

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4. A total of 226 J of heat are absorbed as 58.3 g of lead is heated from 12.0oC to 42.0oC. From this data, what is the specific
Zanzabum
C = Q / M * ΔT

Δf - Δi = 42.0ºC - 12.0ºC = 30.0ºC

C =  226 J / 58.3 * 30.0

C = 226 / 1749

C = 0.129 J/gºC

hope this helps!

6 0
4 years ago
The reform reaction between steam and gaseous methane (CH4) produces "synthesis gas," a mixture of carbon monoxide gas and dihyd
kenny6666 [7]

Answer:

The answer is "= 0.078 \ kg \ H_2".

Explanation:

calculating the moles in CH_4 =\frac{PV}{RT}

                                                =\frac{(0.58 \ atm) \times (923 \ L) }{ (0.0821 \frac{L \cdot atm}{K \cdot mol})(232^{\circ} C +273)}\\\\=\frac{(535.34 \ atm \cdot \ L) }{ (0.0821 \frac{L \cdot atm}{K \cdot mol})(505)K}\\\\=\frac{(535.34 \ atm \cdot \ L) }{ (41.4605 \frac{L \cdot atm}{mol})}\\\\= 12.9 \ mol

Eqution:

CH_4 +H_2O \to  3H_2+ CO \ (g)

Calculating the amount of H_2 produced:

= 12.9 \ mol CH_4 \times  \frac{3 \ mol \ H_2 }{1 \ mol \ CH_4}\times \frac{2.016 g H_2}{1 \ mol \ H_2}\\\\= 78 \ g \ H_2 \\\\= 0.078 \ kg \ H_2

So, the amount of dihydrogen produced = 0.078 \frac{kg}{s}

5 0
3 years ago
What phase of matter is least common on earth
Diano4ka-milaya [45]
Plasma is the least common matter on earth 
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3 years ago
How many metals, nonmetals and metalloids are there in the periodic table?
Ugo [173]

Answer:

95 metals

17 nonmetals

6 metalloids

6 0
3 years ago
Read 2 more answers
How many grams of calcium chloride are dissolved in 5.65 liters of a 0.11 m solution of calcium choride?
Julli [10]
C = 0.11 mol
V = 5.65 L
n = ???

n = C*V
n = 0.11 * 5.65
n = 0.622 mols

1 mol of CaCl2 = 40 + 2*35.5 = 111 grams
0.622 mol = x

x = 111 * 0.622
x = 69.0 grams CaCl2
4 0
3 years ago
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