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Leona [35]
3 years ago
8

A sample of Strontium-90 is found to have decayed to one-fourth of its original amount after 58.2 years. What is the half-life o

f strontium-90?
Chemistry
2 answers:
mafiozo [28]3 years ago
3 0
The half-life of strontium-90 is 28.8 years.
Igoryamba3 years ago
3 0

Answer: Half life of Sr-90 is 29.1 years.

Explanation: Half life is the time in which the substance remains halve of its original amount. Let's say originally we have 100 grams of Sr-90. From given information, it remains one-fourth of its original amount in 58.2 years.

One-fourth of 100 gram will be 25 gram. The equation used for solving this type of problems is:

\frac{N}{N_0}=(0.5)^n

where, n is the number of half lives, N_0 is the original amount of the radioactive substance and N is the remaining amount.

From above information:

N_0 = 100

N = 25

Let's plug in these values in the equation and find out the value of n.

\frac{25}{100}=(0.5)^n

\frac{1}{4}=(0.5)^n

0.25=(0.5)^n

(0.5)^2=(0.5)^n

n = 2

From above calculations, the value of n is 2 means there are two half lives.

From the given time and the value of n, we can calculate the half life of the substance using the equation:

half life = \frac{T}{n}

(Where T stands for time)

Let's plug in the values in the equation:

half life = \frac{58.2years}{2}

half life = 29.1 years

So, half life of Sr-90 is 29.1 years.

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Answer:

See explanation below

Explanation:

I found a picture of this exercise, to show you how to do this problem.

The first picture is the compound, and the second is the mechanism of reaction to do this claisen rearrangement.

Hope this helps

5 0
3 years ago
fish give off the compound ammonia which has a PH above 7. To which class of compounds does ammonia belong?
fiasKO [112]
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3 years ago
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0.450 mol of aluminum hydroxide is allowed to react with 0.550 mol of sulfuric acid; the reaction which ensues is: 2Al(OH)3(s) +
Veseljchak [2.6K]

Answer:

The answer to your question is 1.1 moles of water

Explanation:

                     2Al(OH)₃  +   3H₂SO₄   ⇒   Al₂(SO₄)₃  +   6H₂O

                       0.45 mol      0.55 mol                                ?

Process

1.- Calculate the limiting reactant

Theoretical proportion

       Al(OH)₃ / H₂SO₄ = 2/3 = 0.667

Experimental proportion

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From the proportions, we conclude that the limiting reactant is H₂SO₄

2.- Calculate the moles of H₂O

                        3 moles of H₂SO₄ ----------------  6 moles of water

                        0.55 moles of H₂SO₄ -----------    x

                        x = (0.55 x 6) / 3

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5 0
3 years ago
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xenn [34]

Answer:

a) 2-bromopyrrole

Explanation:

Our options for this questions are:

a) 2-bromopyrrole

b) 2,3-dibromopyrrole

c) N-bromopyrrole

d) 3-bromopyrrole

To understand how the reaction works we have to start with the <u>resonance structures</u>. (Figure 1), on these structures, we will obtain a n<u>egative charge on carbon 2</u> in the pyrrole ring, therefore on this carbon we can generate an attack to an electrophile.

The second step is to check how the mechanism take place. An <u>electrophile is generated</u> by the Br_2 and FeBr_3. This electrophile can be <u>attacked</u> by the negative charge on carbon 2 producing the 2-bromopyrrole. (See figure 2).

I hope it helps!

5 0
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fenix001 [56]
<span>Blood pH has an ideal level of about 7.3 to 7.4. It is important for the pH ofblood to remain constant because if your blood pH varies, itcan be deadly.<span>hope this helps </span></span>
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