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3 years ago

7

Compare electron energy levels and nuclear rings (both physically and chemically)

1 answer:

Nostrana [21]3 years ago

6 0

For electron energy levels, the electrons fill in until the energy level is full, which produces chemical stability. For the nuclear rings, protons and neutrons are physically filled in until the ring is full, which produces nuclear stability.

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The shape of a molecule with no multiple bonds and a central atom with two bonding pairs and too lone pairs of electrons is

My name is Ann [436]

Explanation:

If there are two bond pairs and two lone pairs of electrons the molecular geometry is angular or bent (e.g. H2O). Five electron pairs give a starting point that is a trigonal bipyramidal structure.

3 0

2 years ago

It's almost time for bed but before you're ready to go to sleep you decide to make yourself a cup of hot chocolate and a tasty s

ehidna [41]

1. Milk.

2. What is in the bowl the popcorn, cereal, and pretzels.

3. Hot chocolate and hot milk.

4. Hot chocolate mix.

5. Hot milk.

6. No, because the hot chocolate powder was meant for hot liquids and with cold water it will take longer to dissolve.

You don't have to write exactly as me change it up if you need to hope this helps!!!

8 0

2 years ago

BALANCE the following equations then write the NET IONIC EQUATION for each one: ____Ni(NO 3 ) 2(aq) + ____NaOH (aq) →

Karo-lina-s [1.5K]

Answer:

Ni(NO3)2 + 2NaOH → Ni(OH)2 + 2NaNO3

NET IONIC EQUATION :

Ni +2(aq) + 2(NO3) -1(aq) + 2Na +1(aq) + 2OH -1(aq)

→ Ni(OH)2 (s) + 2Na +1(aq) + 2(NO3) -1(aq)

sorry there is no space to write the reaction in one line...

8 0

2 years ago

The equilibrium constant for the reaction AgBr(s) Picture Ag+(aq) + Br− (aq) is the solubility product constant, Ksp = 7.7 × 10−

barxatty [35]

Answer:

The reaction will be non spontaneous at these concentrations.

Explanation:

$AgBr(s)\rightarrow Ag^+(aq) + Br^- (aq)$

Expression for an equilibrium constant $K_c$ :

$K_c=\frac{[Ag^+][Br^-]}{[AgCl]}=\frac{[Ag^+][Br^-]}{1}=[Ag^+][Br^-]$

Solubility product of the reaction:

$K_{sp}=[Ag^+][Br^-]=K_c=7.7\times 10^{-13}$

Reaction between Gibb's free energy and equilibrium constant if given as:

$\Delta G^o=-2.303\times R\times T\times \log K_c$

$\Delta G^o=-2.303\times R\times T\times \log K_{sp}$

$\Delta G^o=-2.303\times 8.314 J/K mol\times 298 K\times \log[7.7\times 10^{-13}]$

$\Delta G^o=69,117.84 J/mol=69.117 kJ/mol$

Gibb's free energy when concentration $[Ag^+] = 1.0\times 10^{-2} M$ and $[Br^-] = 1.0\times 10^{-3} M$

Reaction quotient of an equilibrium = Q

$Q=[Ag^+][Br^-]=1.0\times 10^{-2} M\times 1.0\times 10^{-3} M=1.0\times 10^{-5}$

$\Delta G=\Delta G^o+(2.303\times R\times T\times \log Q)$

$\Delta G=69.117 kJ/mol+(2.303\times 8.314 Joule/mol K\times 298 K\times \log[1.0\times 10^{-5}])$

$\Delta G=40.588 kJ/mol$

For reaction to spontaneous reaction: $\Delta G$ .
For reaction to non spontaneous reaction: $\Delta G>0$ .

Since ,the value of Gibbs free energy is greater than zero which means reaction will be non spontaneous at these concentrations

5 0

2 years ago

What name is given to a polymer where all of the substituents (i.e., the R groups) are in the same relative orientation (i.e., o

kirza4 [7]

Answer: isotactic

Explanation:

5 0

3 years ago