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Alina [70]
3 years ago
15

3/1 + 1/3 What is the answer to this?

Mathematics
1 answer:
Vika [28.1K]3 years ago
6 0

Answer:

10/3, or 3 1/3.

Step-by-step explanation:

3/1 + 1/3

3 + 1/3

9+1/3

10/3, or 3 1/3.

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Make y the subject of: k=y-1/y
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Concept: Algebraic Manipulation

  1. We want to make y the main variable. Start by moving y to over to one side or multiplying the inverse.
  2. So we have
  3. y =  \frac{1}{1 - k}
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2. Reason How is solving an absolute value equation similar to solving an
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A boat travels 9 km upstream and 9 km back. The time for the round trip is 5 hours. The speed of the stream is 2km/hr. What is t
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What is the measure of angle AEC?
mixer [17]

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6 0
3 years ago
In a 10 mile race, Janet covered the first 2 miles at a constant rate. She then sped up and rode her bike the last 8 miles at a
xenn [34]

Answer:

0.83\text{ miles per minute}

Step-by-step explanation:

GIVEN: In a 10 mile race, Janet covered the first 2 miles at a constant rate. She then speed up and rode her bike the last 8 miles at a rate that was 0.5 miles per minute faster. Janet's overall time would have been 2 minutes faster had she ridden her bike the whole race at the faster pace.

TO FIND: What was Janet's average speed (in miles per minute) for the whole race?

SOLUTION:

let the speed of Janet in first 2\text{ miles}  =x\text{ miles per minute}

speed of Janet's bike in last 8\text{ miles}  =x\text{+0.5 miles per minute}

total time taken by Janet,

\text{Time}=\frac{\text{distance}}{\text{speed}}

\text{Time taken}=\frac{2}{x}+\frac{8}{x+0.5}\text{minute}

Time taken if Janet rides whole race at faster pace =\frac{10}{x+0.5}\text{minute}

 

As, Janet's overall time would have been 2\text{ minutes} faster had she ridden her bike the whole race at the faster pace.

\frac{2}{x}+\frac{8}{x+0.5}=\frac{10}{x+0.5}+2

\frac{2}{x}-\frac{2}{x+0.5}=2

\frac{1}{x}-\frac{1}{x+0.5}=1

x^{2} +0.5x-1=0

on solving we get

x=0.5\text{ miles per minute}

\text{Time taken}=\frac{2}{x}+\frac{8}{x+0.5}\text{minute}

\text{Time taken}=\frac{2}{0.5}+\frac{8}{1}\text{minute}

\text{Time taken}=\frac{2}{x}+\frac{8}{x+0.5}\text{minute}

\text{Time taken}=12\text{minute}

Average speed =\frac{\text{total distance}}{\text{time taken}}

Average speed =\frac{10}{12}=0.83\text{miles per minute}

Therefore average speed of Janet was 0.83\text{ miles per minute}

4 0
3 years ago
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