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malfutka [58]
3 years ago
6

If Claire earns $75 the next week from babysitting and deposits it in her account, what will her balance be then?

Mathematics
2 answers:
SIZIF [17.4K]3 years ago
8 0

Answer:

$75 given that her balance is 0 at the beginning, if she got some money in her account, simply +$75 to the original amount of money

Step-by-step explanation:

nataly862011 [7]3 years ago
5 0
It will be 75$ i guess the question is a bit wrong please recheck
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KengaRu [80]

Answer:

a) Neither arithmetic nor Geometric

Explanation:

Since 99-89.9= 9.1, and 89.9 - 78.8 = 11.1, the sequence is not arithmetic.

Like wise 89.9/99=0.908 and  78.8/89.9 = 0.876 makes it not a geomtric sequence

Step-by-step explanation:

8 0
3 years ago
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A few weeks ago, Vera bought 5 apples from her local farmers' market. Today, she bought 4 apples. What is the percent of decreas
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20% decrease

5-4=1
1÷5×100= 20
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4 years ago
Uncle Malik so the shirt at the rate of 1200 Naira and made a profit of 25% what is the cost price​
uysha [10]

If he made 25 percent profit, the selling price (1200 naira) is 125 percent.

If 125% is equal to 1200 naira

100 percent (the original) will be 100 × 1200 divided by 125

Which is 120000 ÷ 125

Therefore, the cost price is 960 naira

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3 years ago
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Part 3 - Discussion/Explanation Question
SpyIntel [72]

Step-by-step explanation:

Vertical asymptote can be Identites if there is a factor only in the denominator. This means that the function will be infinitely discounted at that point.

For example,

\frac{1}{x - 5}

Set the expression in the denominator equal to 0, because you can't divide by 0.

x - 5 = 0

x = 5

So the vertical asymptote is x=5.

Disclaimer if you see something like this

\frac{(x - 5)(x + 3)}{(x - 5)}

x=5 won't be a vertical asymptote, it will be a hole because it in the numerator and denominator.

Horizontal:

If we have a function like this

\frac{1}{x}

We can determine what happens to the y values as x gets bigger, as x gets bigger, we will get smaller answers for y values. The y values will get closer to 0 but never reach it.

Remember a constant can be represent by

a \times  {x}^{0}

For example,

1 = 1 \times  {x}^{0}

2 =  2 \times {x}^{0}

And so on,

and

x =  {x}^{1}

So our equation is basically

\frac{1 \times  {x}^{0} }{ {x}^{1} }

Look at the degrees, since the numerator has a smaller degree than the denominator, the denominator will grow larger than the numerator as x gets larger, so since the larger number is the denominator, our y values will approach 0.

So anytime, the degree of the numerator < denominator, the horizontal asymptote is x=0.

Consider the function

\frac{3 {x}^{2} }{ {x}^{2}  + 1}

As x get larger, the only thing that will matter will be the leading coefficient of the leading degree term. So as x approach infinity and negative infinity, the horizontal asymptote will the numerator of the leading coefficient/ the leading coefficient of the denominator

So in this case,

x =  \frac{3}{1}

Finally, if the numerator has a greater degree than denominator, the value of horizontal asymptote will be larger and larger such there would be no horizontal asymptote instead of a oblique asymptote.

8 0
2 years ago
Belen has $1.65 deducted from her allowance every time she forgets to do a
zavuch27 [327]

Answer:

9.75

Step-by-step explanation:

1.65 x5 is 8.25 then you add half of 1.65 which is .825 to get 9.75

3 0
2 years ago
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