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3 years ago

Please help I’ll mark you as brainliest if correct

Mathematics

1 answer:

elena-14-01-66 [18.8K]3 years ago

8 0

Answer:

sorry if rong i think its b sorry if rong kk

Step-by-step explanation:

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The sales tax on the model rocket shown is $1.92. What is the percent of sales tax? A drawing of a model rocket with a tag label

astraxan [27]

Answer:

The sales tax is 8%

Explanation:

We are given that:

The price of the rocket is $24 and the sales tax is $1.92

To get the percentage of the sales tax, all we have to do is divide the sales tax by the price of the rocket and then multiply the quotient by 100 (to convert the ratio to percentage)

This is done as follows:

% of sales tax = $\frac{tax}{price}*100$

% of sales tax = $\frac{1.92}{24}*100 = 8$ %

Hope this helps :)

4 0

3 years ago

Before leaving to visit Mexico Levant traded 270 us dollars for 3,000 Mexican pesos when he returned from Mexico, he had 100 pes

In-s [12.5K]

Answer:

Step-by-step explanation:

3,000/ 270 = 11.11

100/ 11.11 = 9

8 0

3 years ago

Determine the equation of the line with slope 3 that passes through the point (2, 0).

Hitman42 [59]

Answer:

m=2y-3

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Enter the correct answer in the box. solve the equation x2 − 16x 54 = 0 by completing the square. fill in the values of a and b

poizon [28]

The roots of the given polynomials exist $x=8+\sqrt{10}$ , and $x=8-\sqrt{10}$ .

<h3>What is the formula of the quadratic equation?</h3>

For a quadratic equation of the form $a x^{2}+b x+c=0$ the solutions are

$x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Therefore by using the formula we have

$x^{2}-16 x+54=0$$

Let, a = 1, b = -16 and c = 54

Substitute the values in the above equation, and we get

$x_{1,2}=\frac{-(-16) \pm \sqrt{(-16)^{2}-4 \cdot 1 \cdot 54}}{2 \cdot 1}$$

simplifying the equation, we get

$$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\$

$$&x_{1}=\frac{-(-16)+2 \sqrt{10}}{2 \cdot 1}, x_{2}=\frac{-(-16)-2 \sqrt{10}}{2 \cdot 1} \\$

$$&x=8+\sqrt{10}, x=8-\sqrt{10}$

Therefore, the roots of the given polynomials are $x=8+\sqrt{10}$ , and

$x=8-\sqrt{10}$ .

To learn more about quadratic equations refer to:

brainly.com/question/1214333

#SPJ4

3 0

1 year ago

Read 2 more answers

What postulate or theorem can be used to prove that these two triangles are congruent?

Diano4ka-milaya [45]

Answer:

ASA

Step-by-step explanation:

in the place that I have put some marks on it, they have the same angle; so then they will also have the same third angle; and for the rest you should use ASA.

8 0

3 years ago