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Morgarella [4.7K]
2 years ago
7

What else is produced during the replacement reaction of silver nitrate and potassium sulfate? 2AgNO3 + K2SO4 Ag2SO4 + ________

Chemistry
2 answers:
NemiM [27]2 years ago
7 0

Answer:

c

Explanation:

OleMash [197]2 years ago
5 0

Answer:

c

Explanation:

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Write orbital diagrams (boxes with arrows in them) to represent the electron configurations of carbon before and after sp hybrid
NemiM [27]
Carbon has an electron configuration of 1s^2 2s^2 2p^2. During sp hybridization, one s and one p orbital of carbon combine to form two sp hybrid orbitals.


4 0
3 years ago
Which of these compounds do not have a pH dependent solubility at less than pH 7.00?
Savatey [412]

Answer:

tbh idekkk

Explanation:

5 0
3 years ago
Objects that are hotter will generally emit _____.
Ede4ka [16]
They emit b) more radiation compared to cooler objects.

This is because hotter objects have more kinetic energy (in order for the particles to vibrate- and so more infrared radiation circulates in its surroundings.)
5 0
3 years ago
What volume of nitrogen gas at STP would react with 37.2 g of magnesium to produce magnesium nitride
anastassius [24]

Answer:

11.58 L of N₂

Explanation:

We'll begin by calculating the number of mole in 37.2 g of magnesium. This can be obtained as follow:

Mass of Mg = 37.2 g

Molar mass of Mg = 24 g/mol

Mole of Mg =?

Mole = mass /Molar mass

Mole of Mg = 37.2 / 24

Mole of Mg = 1.55 moles

Next, we shall write the balanced equation for the reaction. This is illustrated below:

3Mg + N₂ —> Mg₃N₂

From the balanced equation above,

3 moles of Mg reacted with 1 mole of N₂.

Therefore, 1.55 moles of Mg will react with = (1.55 × 1)/3 = 0.517 mole of N₂

Thus, 0.517 mole of N₂ is need for the reaction.

Finally, we shall determine the volume of N₂ needed for the reaction as follow:

Recall:

1 mole of a gas occupies 22.4 L at STP.

1 mole of N₂ occupied 22.4 L at STP.

Therefore, 0.517 mole of N₂ will occupy = 0.517 × 22.4 = 11.58 L at STP

Thus, 11.58 L of N₂ is needed for the reaction.

6 0
3 years ago
What is the boiling point of cyclohexane at 620 mmhg? can you show calculations?
Anton [14]

 Boiling point of cyclohexane at 620 mm hg?  

Standard atmospheric pressure is 760 mm Hg. Boiling point at 760 mm= 80.74˚C  

A liquid boils when its vapor pressure is equal to the atmospheric pressure. The vapor pressure of a liquid is proportional the absolute temperature of the liquid.  

As the atmospheric pressure decreases, less vapor pressure is needed to cause the liquid to boil. Less vapor pressure means lower temperature.  

The boiling point of cyclohexane at 620 mm Hg is less than 80.74˚C



TRY THAT OR THIS

 

271.78

7 0
3 years ago
Read 2 more answers
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