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OleMash [197]
2 years ago
9

Samples with masses of 5.5 g 2.27 g and 0.8995 g are mixed together. The sum of the masses of the three

Chemistry
1 answer:
Nadusha1986 [10]2 years ago
3 0

Answer:

m=8.7g

Explanation:

Hello,

In this case, it is widely known that when measurements with different significant figures are put under mathematical operations, the final result must be displayed with the same amount of significant figures of the shortest measurement, thus, due to the fact that 5.5 g has two significant figures only the result is consequently shown with two significant figures as well as shown down below:

m=5.5g+2.27g+0.8995g\\\\m=8.6695g

By rounding the first six to seven due to the fact that the next six is greater than five, according to rounding rules, the result is:

m=8.7g

Best regards.

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Suggest why it might be difficult and dangerous to test sodium for electrical conductivity?​
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2 years ago
What is the (OH-) in a solution with a pOH of 6.48
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Then we can transform the equation into:

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3 years ago
Consider the following reaction: COCl2(g) ⇌ CO(g) + Cl2(g) A reaction mixture initially contains 1.6 M COCl2. Determine the equi
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Answer:

The equilibrium concentration of CO is 0.0361 M

Explanation:

Step 1: Data given

Kc = 8.33 *10^-4

Molarity of COCl2 = 1.6 M

Step 2: The balanced equation:

COCl2(g) ⇌ CO(g) + Cl2(g)

Step 3: Calculate final concentrations

The initial concentration of COCl2 = 1.6M

The initial concentration of CO and Cl2 = 0M

There will react xM of COCl2

Since the mole ratio is 1:1

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The final concentration of COCl2 will be (1.6 -X)M

Step 4: Define Kc

Kc=  [CO] *[Cl2] /  [COCl2]  = 8.33*10^-4

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8.33 * 10^-4  = X² /(1.6-X)

8.33 * 10^-4 *(1.6 -X) = X²

0.0013328 - 8.33*10^-4 X = X²

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[COCl2] = 1.6 - 0.0361 = 1.5639 M

To control this we can calculate the Kc

(0.0361*0.0361)/1.5639 = 0.000833

5 0
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