Samples with masses of 5.5 g 2.27 g and 0.8995 g are mixed together. The sum of the masses of the three
1 answer:
Answer:
Explanation:
Hello,
In this case, it is widely known that when measurements with different significant figures are put under mathematical operations, the final result must be displayed with the same amount of significant figures of the shortest measurement, thus, due to the fact that 5.5 g has two significant figures only the result is consequently shown with two significant figures as well as shown down below:
By rounding the first six to seven due to the fact that the next six is greater than five, according to rounding rules, the result is:
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Answer:
C ≈ 1.44 × 10⁻³ mol/m³
Explanation:
The given information are;
The liquid volume the pond can hold = 104 m³
The volume of inflow into the pond = 5 m³/h
The volume of outflow into the pond = 5 m³/h
The concentration of the chemical in the inflow water = 0.01 mol/m³
The concentration of the chemical discharged directly into the water = 0.1 mol/h
The concentration, , of chemical that enters the water through inflow per hour is given as follows;
= 0.01 mol/m³ × 5 m³/h = 0.05 mol/h
The concentration, , of chemical that enters the water through direct discharge per hour is given as follows;
= 0.1 mol/h
The total concentration that enters the pond per hour is given as follows;
+
= 0.1 mol/h + 0.05 mol/h = 0.15 mol/h
Whereby the water in the pond properly mixes with the pond, we have;
The concentration of chemicals (C) in the outflow water = 0.15 mol/(104 m³) ≈ 0.00144 mol/m³
C ≈ 1.44 × 10⁻³ mol/m³.