Assume it is 1 litre and weighs 1kg.
2 percent of 1 kg is 20g.
20g divided by molar mass of NaOH.
20g divide by 40 = 0.5 mole
0.5 mole in a litre would be 0.5M
That is the answer: 0.5M
Answer:
103.00
Explanation:
1 mole of Glucose
6 C = 6 * 12 = 72 grams
12H = 12 * 1 = 12 grams
6O = 6 * 16 =96 grams
Total = 180 grams
0.572 moles of Glucose
1 mol of glucose = 180 grams
0.572 mols of glucose = x
x = 0.572 * 180
x = 103.00 grams
Answer: mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm
Explanation: