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4 years ago

When ironing clothes the primary method of heat transfer is conduction convection insulation or radiation

1 answer:

5 0

Conduction, because there is a direct transfer of heat.

When the iron touches the fabric, the heat from the iron gets transferred to the fabric and this is why it is a conduction type of heat transfer.

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A rock sample has a mass of 125 grams and a volume of 50 mL. What is the density of this rock sample?

iris [78.8K]

Answer:

2.5g/ mll

Explanation:

d=m/v

5 0

3 years ago

Identify corresponding correct resonance structures

Vitek1552 [10]

Answer:

III IV first one

Explanation:

sorry if im wrong ~Bread

8 0

2 years ago

What volume (mL) of 7.48x10 -2 M phosphoric acid can be completely reacted with 115 mL of .244 M sodium

Y_Kistochka [10]

Answer:125ml - volume of phosphoic acid

Explanation:

The equation of the reaction is

H3PO4 + 3 NaOH ---> Na3PO4 + 3H2O

Such that I mole of H3PO4 reacts with 3 moles of NaOH to produce the products above.

Given that

M1= Molarity of phosphoric acid = 7.48x10^-2 M

n1= number of moles of phosphoric acid = 1

V1=? ml

M2= Molarity of Sodium hydroxide =0.244 M

V2= volume of sodium hydroxide= 115ml

n2=number of moles of sodium hydroxide = 3

Using the Dilution equation formulae,

M1V1/n1 = M2V2/n2

7.48X10-2 x V1 /1= 0.244M x 115ml/3

V1=0.244Mx115mlx1/0.0748M X 3

V1= 28.06/0.2244= 125.04ml

V1=125.04ml rounded up to 125ml

8 0

3 years ago

50 mol of p4o10 how many moles in p

Novosadov [1.4K]

Is there a picture for that

7 0

3 years ago

Ethylenediamine (en) forms an octahedral complex with Ni2+(aq) with the formula [Ni(en)3]2+. Ni2+(aq) + 3 en ⇌ [Ni(en)3]2+(aq) K

yawa3891 [41]

Answer:

$3.125\times 10^{-19} mol/L$ is the concentration of $Ni^{2+}(aq)$ in the solution.

Explanation:

$Ni^{2+}(aq) + 3 en\rightleftharpoons [Ni(en)_3]^{2+}(aq)$

Concentration of nickel ion = $[Ni^{2+}]=x$

Concentration of nickel complex= $[[Ni(en)_3]^{2+}]=\frac{0.16 mol}{2 L}=0.08 mol/L$

Concentration of ethylenediamine = $[en]=\frac{0.80 mol}{2 L}=0.40 mol/L$

The formation constant of the complex = $K_f=4.0\times 10^{18}$

The expression of formation constant is given as:

$K_f=\frac{[[Ni(en)_3]^{2+}]}{[Ni^{2+}][en]^3}$

$4.0\times 10^{18}=\frac{0.08 mol/L}{x\times (0.40 mol/L)^3}$

$x=\frac{0.08 mol/L}{4.0\times 10^{18}\times (0.40 mol/L)^3}$

$x=3.125\times 10^{-19} mol/L$

$3.125\times 10^{-19} mol/L$ is the concentration of $Ni^{2+}(aq)$ in the solution.

6 0

4 years ago