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pychu [463]
3 years ago
9

Rearrange each jumbled letters

Chemistry
2 answers:
igomit [66]3 years ago
8 0
1. Melting point 2.
boyakko [2]3 years ago
7 0

Answer:

1. MELTING POINT

2. SUBLIMATION

3. FREEZING POINT

4. DEPOSITION

5. HEAT

Explanation:

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How do the products of chemical reactions compare to their reactants?
LUCKY_DIMON [66]

Answer: The products usually weigh more than the reactants.

Explanation:

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Which statement below about contrasting Hb and Mb is FALSE?
olchik [2.2K]

Answer:

C. Hb binds O2 more tightly than Mb.

Explanation:

<u>Hb and Mb are both oxygen carrier protiens which contain the heme group. Hb has 4 heme units in 1 moleucle which work via coperative effect. On the other hand, Mb has only one heme unit. </u>

<u>From above theory, statement A and B are correct.</u>

<u>Although the heme group of the Mb is identical to those of Hb, Mb has a higher affinity for carrying oxygen than hemoglobin.</u>

<u>Hence, Statement C is wrong.</u>

Thats why the function of hemoglobin is to transport oxygen and that of myoglobin is to store oxygen.

<u>When a curve is plotted between oxygen accepted and the pressure of the oxygen, Hb shows sigmoidal, whereas Mb shows hyperbolic oxygen saturation curves.</u><u> The statement D is correct.</u>

<u>Bohr effect and various factors decribe the statement : Hb-oxygen binding is dependent on physiological changes in pH, whereas Mb-oxygen binding is not. </u><u>The  statement E is also correct.</u>

7 0
3 years ago
What is the mass number of sodium
lina2011 [118]

Answer:

Explanation:

Sodium mass number 23, 11 electrons

Magnesium: neutrons = 12

aluminum : atomic number  = 13

phosporus : protons = 15

3 0
3 years ago
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Relate pressure to the area over which a force is applied.
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3 years ago
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ubstance A undergoes a first order reaction A®B with a half-life, t½, of 20 min at 25 °C. If the initial concentration of A in a
Stells [14]

Answer : The concentration of A after 80 min is, 0.100 M

Explanation :

Half-life = 20 min

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{20\text{ min}}

k=3.465\times 10^{-2}\text{ min}^{-1}

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 3.465\times 10^{-2}\text{ min}^{-1}

t = time passed by the sample  = 80 min

a = initial amount of the reactant  = 1.6 M

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

80=\frac{2.303}{3.465\times 10^{-2}}\log\frac{1.6}{a-x}

a-x=0.100M

Therefore, the concentration of A after 80 min is, 0.100 M

3 0
3 years ago
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