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2 years ago

15

X+2y-z = 9 -2x+y+z= 1 2x-y+2z= -5

1 answer:

hodyreva [135]2 years ago

7 0

Answer:

I don't understand the first one

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Ken wants to buy two shirts. The original price of the first shirt is $34, and the original price of the second shirt is $28. Ke

velikii [3]

78 with coupons for the answer!

5 0

2 years ago

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The length of a rectangle is 6 yards longer than its width. If the perimeter of the rectangle is 32 yd, find its area in square

ddd [48]

Let, width = x
Length = x + 6

Now, perimeter, 2(l+b) = 2(x+6+x)
2(2x+6) = 32
4x + 12 = 32
4x = 20
x = 5 &
x+6 = 5+6 = 11

As rectangle's dimensions are 11*5, it's area would be: 11 * 5 = 55 yards²

So, your final answer is 55 Yd²

Hope this helps!

8 0

3 years ago

How would you solve the equation 4x = 100?

LenKa [72]

Answer:

25

Step-by-step explanation:

4x = 100

x = 100/4

x = 25

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2 years ago

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The circle is inscribed in triangle A E C. Which are congruent line segments? Select two options. AB and CB ;EF and ED; ED and C

qaws [65]

Answer:

B and E

aka

E-F and E-D

C-B and C-D

Step-by-step explanation:

4 0

3 years ago

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supervisor records the repair cost for 25 randomly selected dryers. A sample mean of $93.36 and standard deviation of $19.95 are

Simora [160]

<h2><u>Answer with explanation:</u></h2>

The confidence interval for population mean (when population standard deviation is unknown) is given by :-

$\overline{x}-t^*\dfrac{s}{\sqrt{n}}< \mu$

, where n= sample size

$\overline{x}$ = Sample mean

s= sample size

t* = Critical value.

Given : n= 25

Degree of freedom : $df=n-1=24$

$\overline{x}= \$93.36$

$s=\ $19.95$

Significance level for 98% confidence interval : $\alpha=1-0.98=0.02$

Using t-distribution table ,

Two-tailed critical value for 98% confidence interval :

$t^*=t_{\alpha/2,\ df}=t_{0.01,\ 24}=2.4922$

⇒ The critical value that should be used in constructing the confidence interval = 2.4922

Then, the 95% confidence interval would be :-

$93.36-(2.4922)\dfrac{19.95}{\sqrt{25}}< \mu$

$=93.36-9.943878< \mu$

$=93.36-9.943878< \mu$

$=83.416122< \mu$

Hence, the 98% confidence interval for the mean repair cost for the dryers. = $83.4161$

4 0

3 years ago