All categories

3 years ago

The smallest particle an element can be divided into is the A electron B neutron C isotope D atom

Chemistry

2 answers:

zhuklara [117]3 years ago

8 0

Atom the answer is D

padilas [110]3 years ago

4 0

Answer:

D atom

Explanation:

You might be interested in

What volume of 6.58M HCI is needed to make 500. mL of 3.00M HCI?

zmey [24]

Answer:

228 mL

Explanation:

M1*V1 = M2*V2

M1 = 6.58 M

V1 = ?

M2 = 3.00 M

V2 = 500 mL

V1 = M2*V2/M1 = 3.00M*500.mL/6.58 M = 228 mL

3 0

3 years ago

Using the standard reduction potentials, Pb 2+(aq) + 2e– => Pb(s), E° = –0.13 V Fe 2+(aq) + 2e– => Fe(s), E° = –0.44 V Zn

mojhsa [17]

Answer:

Pb(s), Fe(s) and Zn(s) will reduce $Mn^{3+}$ to $Mn^{2+}$

Fe(s) and Zn(s) will reduce $Cr^{3+}$ to $Cr$

Explanation:

Standard reduction potential denotes ability to consume electrons from another species.

Hence, higher the standard reduction potential, higher will be the ability to oxidize another species.

Metal with $E_{red}^{0}$ value lower than 1.51 V will donate electron to $Mn^{3+}$ and thus reduces $Mn^{3+}$ to $Mn^{2+}$ .

So, Pb(s), Fe(s) and Zn(s) will reduce $Mn^{3+}$ to $Mn^{2+}$ .

Metal with $E_{red}^{0}$ value lower than -0.40 V will donate electron to $Cr^{3+}$ and thus reduces $Cr^{3+}$ to $Cr$ .

So, Fe(s) and Zn(s) will reduce $Cr^{3+}$ to $Cr$ .

6 0

3 years ago

Hydrogen-3 (3h) carbon-14 (14c) oxygen-16 (16o) which isotope(s) would most likely undergo nuclear decay, and why? hint: hydroge

denis23 [38]

The correct answer will be:
<span>carbon-14 and hydrogen-3 would most likely decay because their neutrons and protons are not equal.
Due to atoms tend to decay when it has excess of either protons or neutrons
</span>

8 0

3 years ago

Read 2 more answers

An unknown metal forms a soluble compound, M(NO3)2, which then undergoes electrolysis with an applied current of 2.50 amperes. I

frozen [14]

Answer:

The metal is the cathode

The metal is palladium

At the other cathode, the reaction going on is

M(s) ------> M2^+(aq) + 2e

Chlorine can spontaneously react with Pd converting it to Pd^2+

The molar mass of the metal is 106.4 g of M

Explanation:

Given the formula of the compound, M^2+ ion is involved. The equation of the reaction is;

M^2+(aq) + 2e -------------> M(s)

The number of moles of electrons transferred = 2 moles

1 mole of electron = 96500C

And Q= It

Where I= current

t= time taken in seconds

Now;

x g of the metal (its molar mass) is deposited by 2×96500 C

1.87 g of the metal is deposited by (2.50× 22.6×60) C

x = 1.87 × 2×96500/ 2.50 × 22.6 × 60

x= 360910/3390

x= 106.4 g of M

The metal is the cathode

The metal is palladium

At the other cathode, the reaction going on is

M(s) ------> M2^+(aq) + 2e

Chlorine can spontaneously react with Pd converting it to Pd^2+

7 0

3 years ago

CH4->C2H6->C2H5Cl->C4H10->C4H9Br->C4H8<br> Help me please solve this

Nookie1986 [14]

What are you solving for?
C
H
I
R

7 0

3 years ago