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True [87]
3 years ago
13

When the pressure that a gas exerts on a sealed container changes from 1100 bar to 75.5 bar, the temperature changes from k to 2

98 k?
Chemistry
1 answer:
Serjik [45]3 years ago
7 0
Gay-Lussac's law gives the relationship between pressure and temperature of gas. For a fixed amount of gas, pressure is directly proportional to temperature at constant volume.
P/T = k
where P - pressure , T - temperature and k - constant
\frac{P1}{T1} =  \frac{P2}{T2}
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 
substituting the values in the equation 
\frac{1100 bar}{T}  =  \frac{75.5 bar}{298 K}
T = 4342 K
initial temperature was 4342 K
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